javascript Date.js parseExact() 在作为数组传入时不解析 4 位年份
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Date.js parseExact() not parsing 4 digit years when passed in as an array
提问by seanicus
Am I missing something with Date.parseExact() in date.js? According to the api documentation, I should be able to do this:
我是否在 date.js 中遗漏了 Date.parseExact() 的某些内容？根据 api 文档，我应该能够做到这一点：
Date.parseExact("10/15/2004", ["M/d/yyyy", "MMMM d, yyyy"]); // The Date of 15-Oct-2004
That is, I should be able to pass in a string array which contains "...the expected format {String} or an array of expected formats {Array} of the date string." However, when I do this:
也就是说，我应该能够传入一个字符串数组，其中包含“......日期字符串的预期格式 {String} 或预期格式 {Array} 的数组”。但是，当我这样做时：
var d = Date.parseExact($(this).val(), ["MMddyy", "Mddyyyy", "MM/dd/yy","MM/dd/yyyy"])
I get back nulls for dates containing 4 digit years (that is, matching the MMddyyyy and MM/dd/yyyy formats). Am I missing something or is this a bug in Date.js?
对于包含 4 位年份的日期（即匹配 MMddyyyy 和 MM/dd/yyyy 格式），我会返回空值。我是否遗漏了什么或者这是 Date.js 中的错误？
Here is the complete block of code, for context:
这是完整的代码块，用于上下文：
$(function () {
$('#FCSaleDate').change(function (e) {
var d = Date.parseExact($(this).val(), ["MMddyy", "MMddyyyy", "MM/dd/yy","MM/dd/yyyy"])
alert(d.toString("MM/dd/yyyy"));
});
});
回答by Blazemonger
It appears date.js is attempting to parse the four-digit year as a two-digit year, failing, and returning null on failure.
看来 date.js 试图将四位数年份解析为两位数年份，失败并在失败时返回 null。
To prevent this, switch your masks around so it tries the four-digit masks first:
为防止这种情况发生，请切换您的掩码，使其首先尝试四位数掩码：
$(function () {
$('#FCSaleDate').change(function (e) {
var d = Date.parseExact($(this).val(),["MMddyyyy","MMddyy","M/d/yyyy","M/d/yy"]);
alert(d.toString("MM/dd/yyyy"));
});
});
