使用 rpy2 从 python 调用 R 脚本
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/24544190/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Calling R script from python using rpy2
提问by Efferalgan
I'm very new to rpy2, as well as R.
我对 rpy2 和 R 都很陌生。
I basically have a R script, script.R, which contains functions, such as rfunc(folder). It is located in the same directory as my python script. I want to call it from Python, and then launch one of its functions. I do not need any output from this R function. I know it must be very basic, but I cannot find examples of R script-calling python codes. What I am currently doing, in Python:
我基本上有一个 R 脚本 script.R，其中包含函数，例如 rfunc(folder)。它与我的 python 脚本位于同一目录中。我想从 Python 调用它，然后启动它的功能之一。我不需要这个 R 函数的任何输出。我知道它一定是非常基础的，但是我找不到 R 脚本调用 python 代码的例子。我目前正在做的事情，在 Python 中：
import rpy2.robjects as robjects
def pyFunction(folder):
#do python stuff
r=robjects.r
r[r.source("script.R")]
r["rfunc(folder)"]
#do python stuff
pyFunction(folder)
I am getting an error on the line with source:
我在源代码行中收到错误：
r[r.source("script.R")]
File "/usr/lib/python2.7/dist-packages/rpy2/robjects/__init__.py", line 226, in __getitem__
res = _globalenv.get(item)
TypeError: argument 1 must be string, not ListVector
r[r.source("script.R")]
File "/usr/lib/python2.7/dist-packages/rpy2/robjects/__init__.py", line 226, in __getitem__
res = _globalenv.get(item)
TypeError: argument 1 must be string, not ListVector
I quite do not understand how the argument I give it is not a string, and I guess the same problem will then happen on the next line, with folderbeing a python string, and not a R thingie.
我很不明白我给它的参数不是一个字符串，我猜同样的问题会发生在下一行，文件夹是一个 python 字符串，而不是一个 R 的东西。
So, how can I properly call my script?
那么，我该如何正确调用我的脚本呢？
采纳答案by CT Zhu
sourceis a rfunction, which runs a rsource file. Therefore in rpy2, we have two ways to call it, either:
source是一个r函数，它运行一个r源文件。因此，在 中rpy2，我们有两种调用方式：
import rpy2.robjects as robjects
r = robjects.r
r['source']('script.R')
or
或者
import rpy2.robjects as robjects
r = robjects.r
r.source('script.R')
r[r.source("script.R")]is a wrong way to do it.
r[r.source("script.R")]是错误的做法。
Same idea may apply to the next line.
同样的想法可能适用于下一行。
