string 将 Scala 中每个单词的第一个字母大写
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Capitalize the first letter of every word in Scala
提问by Govind Singh
I know this way
我知道这样
val str=org.apache.commons.lang.WordUtils.capitalizeFully("is There any other WAY"))
Want to know is there any other way to do Same.
想知道有没有其他方法可以做到。
something in Scala Style
Scala 风格的东西
回答by Michael Zajac
Capitalize the first letter of a string:
将字符串的第一个字母大写：
"is There any other WAY".capitalize
res8: String = Is There any other WAY
Capitalize the first letter of every word in a string:
将字符串中每个单词的第一个字母大写：
"is There any other WAY".split(' ').map(_.capitalize).mkString(" ")
res9: String = Is There Any Other WAY
Capitalize the first letter of a string, while lower-casing everything else:
将字符串的第一个字母大写，而将其他所有字母小写：
"is There any other WAY".toLowerCase.capitalize
res7: String = Is there any other way
Capitalize the first letter of every word in a string, while lower-casing everything else:
将字符串中每个单词的第一个字母大写，而其他所有内容都小写：
"is There any other WAY".toLowerCase.split(' ').map(_.capitalize).mkString(" ")
res6: String = Is There Any Other Way
回答by Ende Neu
A bit convoluted, you can use split to get a list of strings and then use capitalize, then reduce to get back the string:
有点复杂，您可以使用 split 来获取字符串列表，然后使用大写，然后减少来取回字符串：
scala> "is There any other WAY".split(" ").map(_.capitalize).mkString(" ")
res5: String = Is There Any Other WAY
回答by Eugr
This one will capitalize every word regardless of the separator and doesn't require any additional libraries. It will also handle apostrophe correctly.
无论分隔符如何，这个都将大写每个单词，并且不需要任何额外的库。它还将正确处理撇号。
scala> raw"\b((?<!\b')\w+)".r.replaceAllIn("this is a test, y'all! 'test/test'.", _.group(1).capitalize)
res22: String = This Is A Test, Y'all! 'Test/Test'.
回答by Sergey Povaliaev
To capitalize the first letter of every word despite of a separator:
尽管有分隔符，但要大写每个单词的第一个字母：
scala> import com.ibm.icu.text.BreakIterator
scala> import com.ibm.icu.lang.UCharacter
scala> UCharacter.toTitleCase("is There any-other WAY", BreakIterator.getWordInstance)
res33: String = Is There Any-Other Way
