如何在java8中更改字符串列表中的项目
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how to change items in a list of string in java8
提问by oshai
I want to change all items in list.
What is the correct way to do it with java8?
我想更改list.
正确的做法是什么java8？
public class TestIt {
public static void main(String[] args) {
ArrayList<String> l = new ArrayList<>();
l.add("AB");
l.add("A");
l.add("AA");
l.forEach(x -> x = "b" + x);
System.out.println(l);
}
}
采纳答案by Alexis C.
You can use replaceAll.
您可以使用replaceAll.
Replaces each element of this list with the result of applying the operator to that element.
用将运算符应用于该元素的结果替换此列表的每个元素。
ArrayList<String> l = new ArrayList<>(Arrays.asList("AB","A","AA"));
l.replaceAll(x -> "b" + x);
System.out.println(l);
Output:
输出：
[bAB, bA, bAA]
回答by Roland
If you want to use streams, you can do something like that:
如果你想使用流，你可以这样做：
List<String> l = new ArrayList<>(Arrays.asList("AB","A","AA"));
l = l.stream().map(x -> "b" + x).collect(Collectors.toList());
System.out.println(l);
Output:
输出：
[bAB, bA, bAA]
Of course it is better to use replaceAllif you want to change all elements of a list but using streams enables you to also apply filters or to parallel easily. replaceAllalso modifies the list and throws an exception when the list is unmodifiable, whereas collectcreates a new list.
当然，如果您想更改列表的所有元素，最好使用replaceAll，但使用流使您还可以轻松应用过滤器或并行。replaceAll也会修改列表并在列表不可修改时抛出异常，同时collect创建一个新列表。
