Android ViewPager 上一个/下一个按钮

Android ViewPager Prev/Next Button

提问by Yoda

Okay, so I'm developing an Android app that utilises a ViewPager to display pages.

好的，所以我正在开发一个使用 ViewPager 来显示页面的 Android 应用程序。

Within each page, I have a set of buttons to use for navigating between pages (in addition to the swiping between pages). These buttons are for "first page", "previous page", "next page" and "last page".

在每个页面中，我有一组按钮用于在页面之间导航（除了在页面之间滑动）。这些按钮用于“第一页”、“上一页”、“下一页”和“最后一页”。

What I can't figure out how to do is engineer a mechanism to enable a page change on a button click.

我无法弄清楚如何做的是设计一种机制，以在单击按钮时启用页面更改。

Anyone have any ideas?

谁有想法？

ETA: To better explain the setup, the buttons are declared within each page's layout, and are inflated with the rest of the layout within the PagerAdapter. My problem is that I can't reference the ViewPager from within the PagerAdapter. Or at least, I can't think of a way to do it.

ETA：为了更好地解释设置，按钮在每个页面的布局中声明，并与 PagerAdapter 中的其余布局一起膨胀。我的问题是我无法从 PagerAdapter 中引用 ViewPager。或者至少，我想不出一种方法来做到这一点。

回答by sweggersen

Button:

按钮：

Button yourButton = (Button)findViewById(R.id.button1);
    yourButton.setOnClickListener(new OnClickListener() {

     @Override
           public void onClick(View view) {
               mViewPager.setCurrentItem(getItem(+1), true); //getItem(-1) for previous
           }
        });

Function:

功能：

private int getItem(int i) {
       return mViewPager.getCurrentItem() + i;
}

Hope this helps :)

希望这可以帮助 ：）

回答by Alex Orlov

yourButton.setOnClickListener(new OnClickListener() {
   @Override
   public void onClick(View view) {
      yourViewPager.setCurrentItem(page, smoothScroll);
   }
});

回答by rupinderjeet

A failproof upgrade to sweggersen'sand Alex Orlov'sanswer,

对sweggersen和Alex Orlov 的回答进行了无故障升级，

// For scrolling to next item
nextPageButton.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View view) {
        viewPager.setCurrentItem(getNextPossibleItemIndex(1), true);
    }
});

// For scrolling to previous item
previousPageButton.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View view) {
        viewPager.setCurrentItem(getNextPossibleItemIndex(-1), true);
    }
});

Add getNextPossibleItemIndex() method in your Activity/Fragment,

在您的活动/片段中添加 getNextPossibleItemIndex() 方法，

private int getNextPossibleItemIndex (int change) {

    int currentIndex = viewPager.getCurrentItem();
    int total = viewPager.getAdapter().getCount();

    if (currIndex + change < 0) {
        return 0;
    }

    return Math.abs((currentIndex + change) % total) ;
}

This way, you will be able to change currentItem without worrying about IndexOutOfBoundsException as suggested by Heinrich's comment. Note that using this method, items will be displayed like a circular list.

这样，您将能够更改 currentItem 而不必担心Heinrich 的评论所建议的IndexOutOfBoundsException 。请注意，使用此方法，项目将像圆形列表一样显示。

1 -> 2 -> 3 -> 1 -> 2 -> 3 -> 1

But going back, it will stop at first item

但是回去，它会在第一项停止

1 <- 1 <- 2 <- 3

回答by priti

1) Make layout

1) 进行布局

      <RelativeLayout
                android:layout_width="match_parent"
                android:layout_height="200dp"
                android:background="@color/white"
                android:weightSum="1">



                <android.support.v4.view.ViewPager
                    android:id="@+id/images_pager"
                    android:layout_width="match_parent"
                    android:layout_height="match_parent"
                    >
                </android.support.v4.view.ViewPager>

                <ImageView
                    android:id="@+id/img_next"
                    android:layout_width="35dp"
                    android:layout_height="35dp"
                    android:src="@drawable/forward_white"
                    android:background="@color/colorPrimary"
                    android:layout_centerVertical="true"
                    android:layout_alignParentRight="true"
                    android:layout_marginRight="5dp"
                    android:paddingTop="5dp"
                    android:paddingBottom="5dp"
                    />


                <ImageView
                    android:id="@+id/img_previous"
                    android:layout_width="35dp"
                    android:layout_height="35dp"
                    android:src="@drawable/back_white"
                    android:background="@color/colorPrimary"
                    android:layout_centerVertical="true"
                    android:layout_marginLeft="5dp"
                    android:layout_alignParentLeft="true"
                    android:paddingTop="5dp"
                    android:paddingBottom="5dp"/>


            </RelativeLayout>

2) Set custom Adapter

2) 设置自定义适配器

        CustomViewPagerAdapter  custompageradpter;
        ViewPager   mViewPager;
        mViewPager = (ViewPager)shareImagesDialouge.findViewById(R.id.images_pager); 
         custompageradpter = new CustomViewPagerAdapter(this);
         mViewPager.setAdapter(custompageradpter);

    public class CustomViewPagerAdapter  extends PagerAdapter {


        Context mContext;
        LayoutInflater mLayoutInflater;

        int[] mResources = {
                R.drawable.emoji_1,
                R.drawable.emoji_2,
                R.drawable.emoji_3,
                R.drawable.emoji_4,
                R.drawable.emoji_5,
                R.drawable.emoji_6
        };

        public CustomViewPagerAdapter(Context context) {
            mContext = context;
            mLayoutInflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        }

        @Override
        public int getCount() {
            return mResources.length;
        }

        @Override
        public boolean isViewFromObject(View view, Object object) {
            return view == ((LinearLayout) object);
        }

        @Override
        public Object instantiateItem(ViewGroup container, int position) {
            View itemView = mLayoutInflater.inflate(R.layout.pager_item, container, false);

            ImageView imageView = (ImageView) itemView.findViewById(R.id.imageView);
            imageView.setImageResource(mResources[position]);

            container.addView(itemView);

            return itemView;
        }

        @Override
        public void destroyItem(ViewGroup container, int position, Object object) {
            container.removeView((LinearLayout) object);
        }

    }

3) For next and previous button

3) 对于下一个和上一个按钮

         case R.id.img_previous:
                    mViewPager.setCurrentItem(getItemofviewpager(-1), true);
                    break;

                case R.id.img_next:
                    mViewPager.setCurrentItem(getItemofviewpager(+1), true);
                    break;

4) Make this function

4）做这个功能

  private int getItemofviewpager(int i) {
        return mViewPager.getCurrentItem() + i;
    }

回答by Mr king from Japan

I finished this project with this code.

我用这段代码完成了这个项目。

vPager = (ViewPager) findViewById(R.id.viewpager);
    View tempView1 = inflater.inflate(R.layout.ani_dialog1, null);
    firstView = (ImageView) tempView1.findViewById(R.id.ani_dialog_next);
    views.add(tempView1);
    firstView.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            vPager.setCurrentItem(1, true);

        }
    }); 

回答by Amr Berag

Do it like this:

像这样做：

backButton=(Button)findViewById(R.id.back_button);
nextButton=(Button)findViewById(R.id.next_button);
backButton.setVisibility(View.INVISIBLE);//you can use GONE or even disable it. It depends on your layout 


    nextButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View view) {
            viewPager.setCurrentItem(viewPager.getCurrentItem()+1, true);
        }
    });


    backButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View view) {
            viewPager.setCurrentItem(viewPager.getCurrentItem()-1, true);
        }
    });
}

To prevent IndexOutOfBoundsException you should hide and show the two buttons like this :

为了防止 IndexOutOfBoundsException 你应该像这样隐藏和显示两个按钮：

    viewPager.addOnPageChangeListener(new ViewPager.OnPageChangeListener() {
        @Override
        public void onPageScrolled(int i, float v, int i1) {

        }
        @Override
        public void onPageSelected(int position) {
            if(position==0) {
                backButton.setVisibility(View.INVISIBLE);
            }else  {
                backButton.setVisibility(View.VISIBLE);
            }
            if(position < viewPager.getAdapter().getCount()-1 ) {
                nextButton.setVisibility(View.VISIBLE);
            }else  {
                nextButton.setVisibility(View.INVISIBLE);
            }
        }
        @Override
        public void onPageScrollStateChanged(int i) {

        }
    });

回答by Muhammad Waleed

Update code

更新代码

Button preButton = (Button)findViewById(R.id.pre_button);
        Button nextButton = (Button)findViewById(R.id.next_button);

        preButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                mViewPager.setCurrentItem(mViewPager.getCurrentItem()-1, true); 


            }
        });

        nextButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                mViewPager.setCurrentItem(mViewPager.getCurrentItem()+1, true); 

            }
        });

回答by baasu

First create an interface

首先创建一个接口

public interface OnPageChangedListener {
void OnPageChanged(int position);      }

Next Implement your activity with OnPageChangedListener interface and do the below stuff

接下来使用 OnPageChangedListener 接口实现您的活动并执行以下操作

private void setupViewPager(ViewPager viewPager){
    viewPagerAdapter = new ViewPagerAdapter(getSupportFragmentManager());
    viewPagerAdapter.addFragment(new Fragment1(this));
    viewPagerAdapter.addFragment(new Fragment2(this));
    viewPagerAdapter.addFragment(new Fragment3(this));
    viewPagerAdapter.addFragment(new Fragment4(this));
    viewPagerAdapter.addFragment(new Fragment5(this));
    viewPagerAdapter.addFragment(new Fragment6(this));
    viewPager.setAdapter(viewPagerAdapter);
}
@Override
public void OnPageChanged(int position) {
    viewPager.setCurrentItem(position);
}

In your fragments create a constructor using

在你的片段中创建一个构造函数

private OnPageChangedListener listener;

public Fragment1(OnPageChangedListener listener1) {
    this.listener = listener1;
}

ViewPagerAdapter

ViewPagerAdapter

public class ViewPagerAdapter extends FragmentPagerAdapter {
private final List<Fragment> mFragmentList = new ArrayList<>();

public ViewPagerAdapter(FragmentManager manager) {
    super(manager);
}

@Override
public Fragment getItem(int position) {
    switch (position) {
    }
    return mFragmentList.get(position);
}

@Override
public int getCount() {
    return mFragmentList.size();
}

public void addFragment(Fragment fragment) {
    mFragmentList.add(fragment);
}}

Hope this helps you

希望这对你有帮助

回答by Oto Campos

public void onClick(View v) {
     int currentItem = mViewPager.getCurrentItem();
     mViewPager.setCurrentItem(currentItem+1); //(currentItem-1)
}

only this code in button click: @Override

仅此代码在按钮单击： @Override

getcurrentitemis the actual item in viewpager, the next item is currentItem + 1

getcurrentitem是 中的实际项目viewpager，下一个项目是currentItem + 1