为什么python返回第n+1个列表元素而不是第n个？
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Why does python return the n+1th list element rather than the nth?
提问by useR
i m new to Python and have following problem
我是 Python 新手并且有以下问题
>>> choice = [1,0,1,1,]
>>> choice = [1,0,1,1]
>>> print(choice)
[1, 0, 1, 1]
>>> print(choice[2])
1
why it print 1 rather than 0?
为什么它打印 1 而不是 0？
采纳答案by cribalik
Python uses something that is called zero based indexing, which means that the first element in a list is referred to element number 0and not 1.
Python 使用一种称为基于零的索引，这意味着列表中的第一个元素被引用为元素编号0而不是1。
回答by NPE
It prints 1 because list indices start from zero and not from one. Thus:
它打印 1，因为列表索引从零开始而不是从 1 开始。因此：
choice[0] is 1
choice[1] is 0
choice[2] is 1
choice[3] is 1
回答by Papouche Guinslyzinho
Because of the way math works, Python starts its lists at 0 rather than 1. It seems weird, but there are many advantagesto this, even though it is mostly arbitrary.
由于数学的工作方式，Python 从 0 而不是 1 开始其列表。这看起来很奇怪，但这样做有很多优点，尽管它大多是任意的。
