改造 GSON 将日期从 json 字符串序列化为 java.util.date
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原文地址: http://stackoverflow.com/questions/18473011/
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Retrofit GSON serialize Date from json string into java.util.date
提问by jpotts18
I am using the Retrofit library for my REST calls. Most of what I have done has been smooth as butter but for some reason I am having issues converting JSON timestamp strings into java.util.Date
objects. The JSON that is coming in looks like this.
我正在使用 Retrofit 库进行 REST 调用。我所做的大部分事情都像黄油一样顺利,但出于某种原因,我在将 JSON 时间戳字符串转换为java.util.Date
对象时遇到了问题。传入的 JSON 如下所示。
{
"date": "2013-07-16",
"created_at": "2013-07-16T22:52:36Z",
}
How can I tell Retrofit or Gson to convert these strings into java.util.Date objects
?
我如何告诉 Retrofit 或 Gson 将这些字符串转换为java.util.Date objects
?
采纳答案by gderaco
Gson gson = new GsonBuilder()
.setDateFormat("yyyy-MM-dd'T'HH:mm:ss")
.create();
RestAdapter restAdapter = new RestAdapter.Builder()
.setEndpoint(API_BASE_URL)
.setConverter(new GsonConverter.create(gson))
.build();
Or the Kotlin equivalent:
或 Kotlin 等价物:
val gson = GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss").create()
RestAdapter restAdapter = Retrofit.Builder()
.baseUrl(API_BASE_URL)
.addConverterFactory(GsonConverterFactory.create(gson))
.build()
.create(T::class.java)
You can set your customized Gson parser to retrofit. More here: Retrofit Website
您可以将自定义的 Gson 解析器设置为改造。更多信息:改造网站
Look at Ondreju's response to see how to implement this in retrofit 2.
查看 Ondreju 的回复,了解如何在改造 2 中实现这一点。
回答by giampaolo
Gson can handle only one datetime format (those specified in builder) plus the iso8601 if parsing with custom format is not possible. So, a solution could be to write your custom deserializer. To solve your problem I defined:
如果无法使用自定义格式进行解析,Gson 只能处理一种日期时间格式(在 builder 中指定的格式)和 iso8601。因此,解决方案可能是编写您的自定义解串器。为了解决您的问题,我定义了:
package stackoverflow.questions.q18473011;
import java.util.Date;
public class Foo {
Date date;
Date created_at;
public Foo(Date date, Date created_at){
this.date = date;
this.created_at = created_at;
}
@Override
public String toString() {
return "Foo [date=" + date + ", created_at=" + created_at + "]";
}
}
with this deserializer:
使用这个解串器:
package stackoverflow.questions.q18473011;
import java.lang.reflect.Type;
import java.text.*;
import java.util.Date;
import com.google.gson.*;
public class FooDeserializer implements JsonDeserializer<Foo> {
public Foo deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
String a = json.getAsJsonObject().get("date").getAsString();
String b = json.getAsJsonObject().get("created_at").getAsString();
SimpleDateFormat sdfDate = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat sdfDateWithTime = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'");
Date date, created;
try {
date = sdfDate.parse(a);
created = sdfDateWithTime.parse(b);
} catch (ParseException e) {
throw new RuntimeException(e);
}
return new Foo(date, created);
}
}
Final step is to create a Gson
instance with right adapter:
最后一步是Gson
使用正确的适配器创建一个实例:
package stackoverflow.questions.q18473011;
import com.google.gson.*;
public class Question {
/**
* @param args
*/
public static void main(String[] args) {
String s = "{ \"date\": \"2013-07-16\", \"created_at\": \"2013-07-16T22:52:36Z\"}";
GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(Foo.class, new FooDeserializer());
Gson gson = builder.create();
Foo myObject = gson.fromJson(s, Foo.class);
System.out.println("Result: "+myObject);
}
}
My result:
我的结果:
Result: Foo [date=Tue Jul 16 00:00:00 CEST 2013, created_at=Tue Jul 16 22:52:36 CEST 2013]
回答by Kuanysh Raimbekov
Here is how I did it:
这是我如何做到的:
Create DateTime class extending Date and then write a custom deserializer:
创建扩展 Date 的 DateTime 类,然后编写自定义反序列化器:
public class DateTime extends java.util.Date {
public DateTime(long readLong) {
super(readLong);
}
public DateTime(Date date) {
super(date.getTime());
}
}
Now for the deserializer part where we register both Date and DateTime converters:
现在是我们注册日期和日期时间转换器的解串器部分:
public static Gson gsonWithDate(){
final GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(Date.class, new JsonDeserializer<Date>() {
final DateFormat df = new SimpleDateFormat("yyyy-MM-dd");
@Override
public Date deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
try {
return df.parse(json.getAsString());
} catch (final java.text.ParseException e) {
e.printStackTrace();
return null;
}
}
});
builder.registerTypeAdapter(DateTime.class, new JsonDeserializer<DateTime>() {
final DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
@Override
public DateTime deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
try {
return new DateTime(df.parse(json.getAsString()));
} catch (final java.text.ParseException e) {
e.printStackTrace();
return null;
}
}
});
return builder.create();
}
And when you create your RestAdapter, do the following:
创建 RestAdapter 时,请执行以下操作:
new RestAdapter.Builder().setConverter(gsonWithDate());
Your Foo should look like this:
你的 Foo 应该是这样的:
class Foo {
Date date;
DateTime created_at;
}
回答by cpoole
Quite literally if you already have an Date object with the name "created_at" in the class you are creating then it is this easy:
从字面上看,如果您在创建的类中已经有一个名为“created_at”的 Date 对象,那么这很简单:
Gson gson = new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'").create();
YourObject parsedObject1 = gson.fromJson(JsonStringYouGotSomehow, YourObject.class);
And you're done. no complicated overriding needed.
你已经完成了。不需要复杂的覆盖。
回答by shiami
You can define two new classes like this:
您可以像这样定义两个新类:
import java.util.Date;
public class MyDate extends Date {
}
and
和
import java.util.Date;
public class CreatedAtDate extends Date {
}
Your POJO will be like this:
你的 POJO 将是这样的:
import MyDate;
import CreatedAtDate;
public class Foo {
MyDate date;
CreatedAtDate created_at;
}
Finally set your custom deserializer:
最后设置您的自定义解串器:
public class MyDateDeserializer implements JsonDeserializer<Date> {
public static final SimpleDateFormat sServerDateDateFormat = new SimpleDateFormat("yyyy-MM-dd");
@Override
public MyDate deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
if (json != null) {
final String jsonString = json.getAsString();
try {
return (MyDate) sServerDateDateFormat.parse(jsonString);
} catch (ParseException e) {
e.printStackTrace();
}
}
return null;
}
}
and
和
GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(MyDate.class, new MyDateDeserializer());
回答by Andrzej Purtak
@gderaco's answer updated to retrofit 2.0:
@gderaco 的答案更新为改造 2.0:
Gson gson = new GsonBuilder()
.setDateFormat("yyyy-MM-dd'T'HH:mm:ss")
.create();
Retrofit retrofitAdapter = new Retrofit.Builder()
.baseUrl(API_BASE_URL)
.addConverterFactory(GsonConverterFactory.create(gson))
.build();