java JAVA中未处理的异常类型
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Unhandled Exception Type in JAVA
提问by Will
I have a two classes in the same package in JAVA.
我在 JAVA 的同一个包中有两个类。
One class in which I have a constructor an exception I tried to create myself:
我有一个构造函数的一个类，我试图自己创建一个异常：
public class ZooException extends Exception {
public ZooException(String error) {
super(error);
}
}
Another class needs to call this exception at one point:
另一个类需要在某一时刻调用这个异常：
public class Zoo<T extends Animal>
Zoo(int capacity) {
if (capacity <= 1) {
throw new ZooException("Zoo capacity must be larger than zero");
}
}
I notice two things here
我注意到两件事
- In the ZooException class, I get a warning: "The serializable class CageException does not declare a static final serialVersionUID field of type long"
- In the Zoo class, on the line that starts with "throw new", I get a compile error: "Unhandled exception type CageException"
- 在 ZooException 类中，我收到一条警告：“可序列化类 CageException 未声明 long 类型的静态最终 serialVersionUID 字段”
- 在 Zoo 类中，在以“throw new”开头的那一行，我得到一个编译错误：“Unhandled exception type CageException”
Any ideas on what I can do to solve this error in the Zoo class? Thank you in advance!
关于我可以做些什么来解决 Zoo 类中的这个错误的任何想法？先感谢您！
回答by Will
You are extending Exception, a checked exception, this means that any method which throws that exception needs to say so:
您正在扩展Exception一个已检查的异常，这意味着抛出该异常的任何方法都需要这样说：
Zoo(int capacity) throws ZooException {
And any code calling that constructor will have to try {} catch {}or throw it again.
任何调用该构造函数的代码都将不得不try {} catch {}或再次抛出它。
If you don't want it to be checked, use extends RuntimeExceptioninstead
如果您不想检查它，请extends RuntimeException改用
回答by Mordechai
About unchecked exceptions @Will Pis right.
关于未经检查的异常@Will P是对的。
About serialVersionUID, this means - since Exception is Serializable - if you anytime decide that a previous version of your class should be incompatible with your newer version ( usually for public APIs), for example, that class had undergone major changes, simply change the unique id, and reading an object of the old version would throw an exception.
关于serialVersionUID，这意味着——因为异常是可序列化的——如果你任何时候决定你的类的先前版本应该与你的新版本不兼容（通常用于公共API），例如，该类发生了重大变化，只需更改唯一的id，读取旧版本的对象会抛出异常。
回答by Aurand
Zoo(int capacity) throws ZooException {
if (capacity <= 1) {
throw new ZooException("Zoo capacity must be larger than zero");
}
You must declare checked exceptions or handle them with a try-catch bock. Try reading up on exceptions: http://docs.oracle.com/javase/tutorial/essential/exceptions/
您必须声明已检查的异常或使用 try-catch 块处理它们。尝试阅读异常：http: //docs.oracle.com/javase/tutorial/essential/exceptions/
