javascript 日期差异
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javascript date difference
提问by williamparry
I've looked at: Get difference between 2 dates in javascript?
我看过：在 javascript 中获取两个日期之间的差异？
And I still can't get this to work.
我仍然无法让它发挥作用。
var difference = data.List[0].EndDate - Math.round(new Date().getTime()/1000.0) * 1000;
var daysRemaining = Math.floor(difference / 1000 / 60 / 60 / 24);
var hoursRemaining = Math.floor(difference / 1000 / 60 / 60 - (24 * daysRemaining));
var minutesRemaining = Math.floor(difference / 1000 / 60 - (24 * 60 * daysRemaining) - (60 * hoursRemaining));
var secondsRemaining = Math.floor(difference / 1000 - (24 * 60 * 60 * daysRemaining) - (60 * 60 * hoursRemaining) - (60 * minutesRemaining));
data.List[0].EndDate is a UTC number (like: 1291427809310 (http://www.epochconverter.com/)) that will always be later than the current date.
data.List[0].EndDate 是一个 UTC 数字（如：1291427809310（http://www.epochconverter.com/）），它总是晚于当前日期。
回答by Devil's Advocate
function days_between(date1, date2) {
// The number of milliseconds in one day
var ONE_DAY = 1000 * 60 * 60 * 24
// Convert both dates to milliseconds
var date1_ms = date1.getTime()
var date2_ms = date2.getTime()
// Calculate the difference in milliseconds
var difference_ms = Math.abs(date1_ms - date2_ms)
// Convert back to days and return
return Math.round(difference_ms/ONE_DAY)
}
回答by Devil's Advocate
回答by epascarello
You say that UTC timestamp is "2004-09-16T23:59:58.75"?
你说UTC时间戳是“2004-09-16T23:59:58.75”？
So you are basically doing
所以你基本上是在做
var x = "2004-09-16T23:59:58.75" - 123456
Now that you clarified that, than the above does not apply. You new issue is the number of milliseconds is in the past so when you do the difference calculation, you are getting a negative number. You probably want to swap the order around.
既然您澄清了这一点，以上内容并不适用。您的新问题是过去的毫秒数，因此当您进行差异计算时，您会得到一个负数。您可能想要交换顺序。
var difference = new Date().getTime()-data.List[0].EndDate;
回答by Dan Grossman
If EndDate is in milliseconds, and getTime() returns milliseconds, why do you divide it by 1000 only to multiply it by 1000 in the same line? And if you only need second precision for all the rest of the code, why work in milliseconds? Start out with a number of seconds to simplify all your calculations:
如果 EndDate 以毫秒为单位，并且 getTime() 返回毫秒，为什么在同一行中将其除以 1000 却只乘以 1000？如果您只需要所有其余代码的第二个精度，为什么要以毫秒为单位？从几秒钟开始以简化您的所有计算：
var difference = Math.round((data.List[0].EndDate - new Date().getTime()) / 1000);
