java 将 int 数组转换为字符串变量
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Convert int array to string variable
提问by Berkan
I have an integer array that keeps binary numbers 0 and 1 in itself. I want to convert my integer array to a string variable in java. How can I do it?
我有一个整数数组，它本身保留二进制数 0 和 1。我想将我的整数数组转换为 java 中的字符串变量。我该怎么做？
回答by Jo?o Silva
int[] arr = new int[] { 1, 0, 1, 0 };
StringBuilder sb = new StringBuilder(arr.length);
for (int i : arr) {
sb.append(i);
}
String s = sb.toString(); // 1010
If you don't mind having brackets around your string, and your numbers separated by a comma, you can use Arrays.toStringas suggested by others.
如果您不介意在字符串周围使用括号，并且您的数字用逗号分隔，则可以Arrays.toString按照其他人的建议使用。
回答by ShyJ
Probably Arrays.toString(int[])is what you are looking for.
可能Arrays.toString(int[])就是你要找的。
final int[] sample = new int[] {1, 2, 3};
final String arrayStr = Arrays.toString (sample);
System.out.println (arrayStr);
This should print [1, 2, 3].
这应该打印 [1, 2, 3]。
Here is a fiddlefor it.
这是一个小提琴。
回答by Alexander Pogrebnyak
This is one way of doing it:
这是一种方法：
String stringVar = java.util.Arrays.toString( intArray );
回答by zapl
You can also do it manually like this
你也可以像这样手动完成
private static String format(int[] array) {
StringBuilder sb = new StringBuilder();
boolean needSeparator = false;
for (int number : array) {
if (needSeparator) {
sb.append(", ");
}
if (number != 0) {
sb.append("true");
} else {
sb.append("false");
}
needSeparator = true;
}
return sb.toString();
}
That would be especially useful if you want to use a special format. Above example will produce strings like "true, false, true"
如果您想使用特殊格式，这将特别有用。上面的例子将产生像这样的字符串"true, false, true"
And a fiddle.
还有一把小提琴。
Edit: oops, trueshould be != 0, not !=1. Corrected in above code, broken in fiddle
编辑：哎呀，true应该是!= 0，不是!=1。在上面的代码中更正，在小提琴中损坏
