java 嵌套对象的杰克逊序列化
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Hymanson serialization of nested objects
提问by Anar Amrastanov
I have problem with Hymanson serialization of object by its interface.
我在通过接口对对象进行 Hymanson 序列化时遇到问题。
I have class
我有课
class Point implements PointView {
private String id;
private String name;
public Point() {
}
public Point(String id, String name) {
this.id = id;
this.name = name;
}
@Override
public String getId() {
return id;
}
public String getName() {
return name;
}
}
which implements
其中实现
interface PointView {
String getId();
}
and have class
并上课
class Map implements MapView {
private String id;
private String name;
private Point point;
public Map() {
}
public Map(String id, String name, Point point) {
this.id = id;
this.name = name;
this.point = point;
}
@Override
public String getId() {
return id;
}
public String getName() {
return name;
}
@JsonSerialize(as = PointView.class)
public Point getPoint() {
return point;
}
}
which implements
其中实现
interface MapView {
String getId();
Point getPoint();
}
And have class
并上课
class Container {
private Map map;
public Container() {
}
public Container(Map map) {
this.map = map;
}
@JsonSerialize(as = MapView.class)
public Map getMap() {
return map;
}
}
I want serialize Container with Hymanson and get result
我想用 Hymanson 序列化 Container 并得到结果
{"map":{"id":"mapId","point":{"id":"pointId"}}}
But in fact I get result
但实际上我得到了结果
{"map":{"id":"mapId","point":{"id":"pointId","name":"pointName"}}}
that have property "name" in nested object "point" although I specified serializition type of Point in Map (@JsonSerialize(as = PointView.class)). Interface PointView dont have method getName, but in result exists field "name" of Point.
尽管我在 Map ( @JsonSerialize(as = PointView.class)) 中指定了 Point 的序列化类型，但在嵌套对象“point”中具有属性“name” 。接口 PointView 没有方法 getName，但在结果中存在 Point 的字段“名称”。
If I remove annotation (@JsonSerialize(as = MapView.class)) from method getMap in class Container I get result
如果我@JsonSerialize(as = MapView.class)从类 Container 中的方法 getMap 中删除注释（），我会得到结果
{"map":{"id":"mapId","name":"mapName","point":{"id":"pointId"}}}
Now point dont have property "name", but map have.
现在点没有属性“名称”，但地图有。
How can I get result
我怎样才能得到结果
{"map":{"id":"mapId","point":{"id":"pointId"}}}
?
?
采纳答案by Anar Amrastanov
To get the desired result also the same method in interface must be annotated by @JsonSerialize
要获得所需的结果，接口中的相同方法也必须由 @JsonSerialize
interface MapView {
String getId();
@JsonSerialize(as = PointView.class)
Point getPoint();
}
回答by Bohemian
You can annotate the method like this:
您可以像这样注释方法：
@JsonIgnore
public String getName() {
return name;
}
Or if you want specific serialization in this use case, but normal serialization in others, you can use a @JsonView(see doc).
或者，如果您想要在此用例中进行特定序列化，而在其他用例中进行正常序列化，则可以使用 a @JsonView（请参阅doc）。
The reason it's serializing out the nameis that the instancehas the accessor getName(), even though interface does not.
它序列化的原因name是实例具有访问器getName()，即使接口没有。
回答by StaxMan
Yes, you can use
是的，你可以使用
@JsonSerialize(as=MyInterface.class)
public class ConcreteClass implements MyInterface { .... }
either on implementation class (as above), or on property that has value.
在实现类（如上）或具有值的属性上。
