C++ 在C++中查找字符串中特殊字符的索引
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Find the index of a special character in string in C++
提问by rain
I wanna know if there is any standard function in visual stodio 2010, C++, which takes a character, and returns the index of it in special string, if it is exist in the string. Tnx
我想知道visual stodio 2010，C++中是否有任何标准函数，它接受一个字符，并在特殊字符串中返回它的索引，如果它存在于字符串中。Tnx
采纳答案by Pablo Santa Cruz
You can use std::strchr.
您可以使用std::strchr.
If you have a Clike string:
如果你有一个类似C 的字符串：
const char *s = "hello, weird + char.";
strchr(s, '+'); // will return 13, which is '+' position within string
If you have a std::stringinstance:
如果您有一个std::string实例：
std::string s = "hello, weird + char.";
strchr(s.c_str(), '+'); // 13!
With a std::stringyou can also a method on it to find the character you are looking for.
使用 astd::string您还可以使用一种方法来查找您要查找的字符。
回答by NPE
strchror std::string::find, depending on the type of string?
strchr或者std::string::find，取决于字符串的类型？
回答by DanS
strchr() returns a pointer to the character in the string.
strchr() 返回指向字符串中字符的指针。
const char *s = "hello, weird + char.";
char *pc = strchr(s, '+'); // returns a pointer to '+' in the string
int idx = pc - s; // idx 13, which is '+' position within string
回答by Jo?o Víctor
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main() {
string text = "this is a sample string";
string target = "sample";
int idx = text.find(target);
if (idx!=string::npos) {
cout << "find at index: " << idx << endl;
} else {
cout << "not found" << endl;
}
return 0;
}
