windows 将一个 C 程序的输出获取到另一个 C 程序中的变量中
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Get the output of one C program into a variable in another C program
提问by Ronin
I have 2 C programs.
Say one is program-1.c
我有 2 个 C 程序。说一个是program-1.c
int main(){
printf("hello world");
}
Now in 2nd code named program-2.c, I want the output of 1st code into a variable,
so that I can have the output "hello world" into a variable in the 2nd C code.
现在在名为 的第二个代码中program-2.c，我希望将第一个代码的输出转换为变量，以便我可以将输出“hello world”转换为第二个 C 代码中的变量。
How can I do this?
我怎样才能做到这一点？
回答by Mat
You can use the popenfunction for this:
您可以popen为此使用该功能：
FILE* proc1 = popen("./program1", "r");
// Usual error handling code goes here
// use the usual FILE* read functions
pclose(proc1);
回答by Alok Save
You will need to run the two programs in two separate processes and then use some sort of IPC mechanism to exchange data between the two processes.
您需要在两个单独的进程中运行这两个程序，然后使用某种 IPC 机制在两个进程之间交换数据。
回答by Bo Persson
On many operating systems you can get the output from one console program as input to the next, perhaps
在许多操作系统上，您可以将一个控制台程序的输出作为下一个程序的输入，也许
program-1 > program-2
you can then read the result from standard input
然后您可以从标准输入读取结果
std::string variable;
std::getline(std::cin, variable);
回答by Vinay Jain
Sample Code for "Output of one program is input of another program Using Pipes"
“一个程序的输出是另一个程序使用管道的输入”的示例代码
#include <unistd.h>
#include <process.h>
/* Pipe the output of program to the input of another. */
int main()
{
int pipe_fds[2];
int stdin_save, stdout_save;
if (pipe(pipe_fds) < 0)
return -1;
/* Duplicate stdin and stdout so we can restore them later. */
stdin_save = dup(STDIN_FILENO);
stdout_save = dup(STDOUT_FILENO);
/* Make the write end of the pipe stdout. */
dup2(pipe_fds[1], STDOUT_FILENO);
/* Run the program. Its output will be written to the pipe. */
spawnl(P_WAIT, "/dev/env/DJDIR/bin/ls.exe", "ls.exe", NULL);
/* Close the write end of the pipe. */
close(pipe_fds[1]);
/* Restore stdout. */
dup2(stdout_save, STDOUT_FILENO);
/* Make the read end of the pipe stdin. */
dup2(pipe_fds[0], STDIN_FILENO);
/* Run another program. Its input will come from the output of the
first program. */
spawnl(P_WAIT, "/dev/env/DJDIR/bin/less.exe", "less.exe", "-E", NULL);
/* Close the read end of the pipe. */
close(pipe_fds[0]);
/* Restore stdin. */
dup2(stdin_save, STDIN_FILENO);
return 0;
}
Cheers....
干杯....
回答by Vinay Jain
On windows u can use this example...
在 Windows 上你可以使用这个例子......
#include <iostream>
#include<time.h>
?
using namespace std;
?
int main()
{
int a=34, b=40;
?
while(1)
{
usleep(300000);?
cout << a << " " << b << endl;
}
}
#include<iostream>
?
using namespace std;
?
int main()
{
int a, b;
?
while(1)
{
cin.clear();
?
cin >> a >> b;
?
if (!cin) continue;
?
cout << a << " " << b << endl;
}
}
You have to observe and set the usleep() value to successfully get the input from the output of the other program. Run both programs simultaneously. Enjoy..:)
您必须观察并设置 usleep() 值才能成功从其他程序的输出中获取输入。同时运行两个程序。享受..：）
回答by user1129769
In the code for the program-2.c you should use int argcand char *argv[]to get the output from program-1.c
在 program-2.c 的代码中，您应该使用int argc和char *argv[]从 program-1.c 获取输出
So program-2.c should look like this:
所以 program-2.c 应该是这样的：
void main(int argc, char *argv[])
{
int i;
for( i=0; i<argc; i++ )
{
printf("%s", argv[i]); //Do whatever you want with argv[i]
}
}
Then in the command prompt program-1 > program-2
然后在命令提示符 program-1 > program-2
