php 最简单的php下拉框
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时间：2020-08-25 13:36:18 来源:igfitidea点击:
simplest php dropdown box
提问by John
I have a simple dropdow box, I want to get the value of the selected item with php. If anyone can help me with it please.
我有一个简单的下拉框，我想用 php 获取所选项目的值。如果有人可以帮助我，请。
<form id="s" method="post">
<select name="size">
<option value="small">Small</option>
<option value="medium">Medium</option>
<option value="large">Large</option>
</select>
<input type="submit" name="Submit" value="Send">
</form>
<?php
---
echo "selected size".$selected;
?>
回答by StasM
Provided you put everything in one file:
如果您将所有内容都放在一个文件中：
<form id="s" method="post">
<select name="size">
<option value="small">Small</option>
<option value="medium">Medium</option>
<option value="large">Large</option>
</select>
<input type="submit" name="Submit" value="Send">
</form>
<?php
if(isset($_POST['size'])) {
echo "selected size: ".htmlspecialchars($_POST['size']);
}
?>
