java android获取和解析谷歌路线

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时间:2020-10-29 23:43:58  来源:igfitidea点击:

android get and parse Google Directions

javaandroidgoogle-maps

提问by urobo

google Directions API

谷歌路线API

I read this guide now I can build a correct request to receive the xml file containg the directions from address A to address B. What I need is some instructions and example on how to read this xml to draw the obtained directions on an Android MapView. I'd like also to know what represents this tag in the xml:

我现在阅读了本指南,我可以构建一个正确的请求来接收包含从地址 A 到地址 B 的路线的 xml 文件。我需要一些说明和示例,了解如何读取此 xml 以在 Android MapView 上绘制获得的路线。我还想知道什么在 xml 中代表这个标签:

<overview_polyline>
<points>
a~l~Fjk~uOnzh@vlbBtc~@tsE`vnApw{A`dw@~w\|tNtqf@l{Yd_Fblh@rxo@b}
@xxSfytAblk@xxaBeJxlcBb~t@zbh@jc|Bx}C`rv@rw|@rlhA~dVzeo@vrSnc}Axf]fjz@
xfFbw~@dz{A~d{A|zOxbrBbdUvpo@`cFp~xBc`Hk@nurDznmFfwMbwz@bbl@lq~@lo
Ppxq@bw_@v|{CbtY~jGqeMb{iF|n\~mbDzeVh_Wr|Efc\x`Ij{kE}mAb~uF{cNd}xBjp]
fulBiwJpgg@|kHntyArpb@bijCk_Kv~eGyqTj_|@`uV`k|DcsNdwxAott@r}q@_gc@nu`CnvH
x`k@dse@j|p@zpiAp|gEicy@`omFvaErfo@igQxnlApqGze~AsyRzrjAb__@ftyB}pIlo_B
flmA~yQftNboWzoAlzp@mz`@|}_@fda@jakEitAn{fB_a]lexClshBtmqAdmY_hLxiZd~XtaBndgC
</points>
<levels>BBBAAAAABAABAAAAAABBAAABBAAAABBAAABABAAABABBAABAABAAAABABABABBABAABB</levels> 
</overview_polyline> 

thanks

谢谢

回答by urobo

I found this example on the web I'll try to use it. polyline decoding example

我在网上找到了这个例子,我会尝试使用它。折线解码示例

private List<GeoPoint> decodePoly(String encoded) {

  List<GeoPoint> poly = new ArrayList<GeoPoint>();
  int index = 0, len = encoded.length();
  int lat = 0, lng = 0;

  while (index < len) {
      int b, shift = 0, result = 0;
      do {
          b = encoded.charAt(index++) - 63;
          result |= (b & 0x1f) << shift;
          shift += 5;
      } while (b >= 0x20);
      int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
      lat += dlat;

      shift = 0;
      result = 0;
      do {
          b = encoded.charAt(index++) - 63;
          result |= (b & 0x1f) << shift;
          shift += 5;
      } while (b >= 0x20);
      int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
      lng += dlng;

      GeoPoint p = new GeoPoint((int) (((double) lat / 1E5) * 1E6),
           (int) (((double) lng / 1E5) * 1E6));
      poly.add(p);
  }

  return poly;
}

回答by Mathias Seguy Android2ee

I was also trying to use the Direction Api of Google in Android. So I made an open source project to help doing that. You can find it here:https://github.com/MathiasSeguy-Android2EE/GDirectionsApiUtils

我还尝试在 Android 中使用 Google 的 Direction Api。所以我做了一个开源项目来帮助做到这一点。你可以在这里找到它:https: //github.com/MathiasSeguy-Android2EE/GDirectionsApiUtils

How it works, definitly simply:

它是如何工作的,绝对简单:

public class MainActivity extends ActionBarActivity implements DCACallBack{
/**
 * Get the Google Direction between mDevice location and the touched location using the     Walk
 * @param point
 */
private void getDirections(LatLng point) {
     GDirectionsApiUtils.getDirection(this, startPoint, endPoint, GDirectionsApiUtils.MODE_WALKING);
}

/*
 * The callback
 * When the directions is built from the google server and parsed, this method is called and give you the expected direction
 */
@Override
public void onDirectionLoaded(List<GDirection> directions) {        
    // Display the direction or use the DirectionsApiUtils
    for(GDirection direction:directions) {
        Log.e("MainActivity", "onDirectionLoaded : Draw GDirections Called with path " + directions);
        GDirectionsApiUtils.drawGDirection(direction, mMap);
    }
}

回答by Ankhwatcher

I've tweaked urobo's answer above (very slightly) to give you LatLngs which you'll want for Google Maps for Android V2:

我已经调整了上面 urobo 的答案(非常轻微),以便为您提供 LatLngs,您需要在 Android V2 版 Google 地图中使用它:

private List<LatLng> decodePoly(String encoded) {

    List<LatLng> poly = new ArrayList<LatLng>();
    int index = 0, len = encoded.length();
    int lat = 0, lng = 0;

    while (index < len) {
        int b, shift = 0, result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lat += dlat;

        shift = 0;
        result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lng += dlng;

        LatLng p = new LatLng((double) lat / 1E5, (double) lng / 1E5);
        poly.add(p);
    }
    return poly;
}

回答by Rajan Twanabashu

you might want to have a quick view of the route that will be created by the waypoint_polyline and the coordinate list directly. For this google have release decoding api "Interactive Polyline Encoder Utility"

您可能希望快速查看由 waypoint_polyline 和坐标列表直接创建的路线。为此,谷歌发布了解码 API“交互式折线编码器实用程序”

You can paste the waypoint_polyline value to Encoded Polyline text field at address Interactive Polyline Encoder Utility

您可以将 waypoint_polyline 值粘贴到地址Interactive Polyline Encoder Utility处的 Encoded Polyline 文本字段