没有类类型 C++
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does not have class type C++
提问by JaredC
This is one class from my program! When I'm trying to compile the whole program, I get an error message like this:
这是我程序中的一节课！当我尝试编译整个程序时，我收到如下错误消息：
main.cpp:174: error: '((Scene*)this)->Scene::lake' does not have class type
main.cpp:174: 错误：'((Scene*)this)->Scene::lake' 没有类类型
The source
来源
class Scene
{
int L,Dist;
Background back ;
Lake lake(int L);
IceSkater iceskater(int Dist);
public :
Scene(int L, int Dist)
{
cout<<"Scene was just created"<<endl;
}
~Scene()
{
cout<<"Scene is about to be destroyed !"<<endl;
}
};
回答by JaredC
Your problem is in the following line:
您的问题在以下行中：
Lake lake(int L);
If you're just trying to declare a Lakeobject then you probably want to remove the (int L). What you have there is declaring a function lakethat returns a Lakeand accepts an intas a parameter.
如果您只是想声明一个Lake对象，那么您可能想要删除(int L). 您所拥有的是声明一个lake返回 aLake并接受 anint作为参数的函数。
If you're trying to pass in L when constructing your lakeobject, then I think you want your code to look like this:
如果您在构建lake对象时尝试传入 L ，那么我认为您希望您的代码如下所示：
class Scene
{
int L,Dist;
Background back ;
Lake lake;
IceSkater iceskater;
public :
Scene(int L, int Dist) :
L(L),
Dist(Dist),
lake(L),
iceskater(Dist)
{
cout<<"Scene was just created"<<endl;
}
.....
Notice the 4 lines added to your constructor. This is called member initialization, and its how you construct member variables. Read more about it in this faq. Or some other tidbits I found hereand here.
注意添加到构造函数中的 4 行。这称为成员初始化，以及如何构造成员变量。在此常见问题解答中阅读更多相关信息。或者我在这里和这里找到的其他一些花絮。
回答by Stuart Golodetz
You declare lakeas a method that takes one argument and returns a Lake. You then try and call a method on it via lake.light_up(). This causes the error you observe.
您声明lake为一个方法，它接受一个参数并返回一个Lake. 然后，您尝试通过lake.light_up(). 这会导致您观察到的错误。
To solve the problem, you either need to declare laketo be a variable, e.g. Lake lake;, or you need to stop trying to call a method on it.
为了解决这个问题，你要么需要声明lake为一个变量，例如Lake lake;，要么你需要停止尝试调用它的方法。
回答by Jerry Coffin
You've declared (but never defined) lakeas a member function of Scene:
您已声明（但从未定义）lake为 Scene 的成员函数：
class Scene
{
// ...
Lake lake(int L);
But then in plot, you try to use lakeas if it were a variable:
但是在 中plot，您尝试将lake其用作变量：
int plot()
{
lake.light_up();
回答by Ayush Jindal
Replace the line Lake lake(int L);with Lake lake= Lake(L);or with this: Lake lake{L};
Lake lake(int L);用Lake lake= Lake(L);或替换该行：Lake lake{L};
