java 如何从 EasyMock.anyObject(List.class) 调用中删除警告
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3875480/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How do I remove the warning from a EasyMock.anyObject(List.class) call
提问by Drahakar
Compiler can't stop complaining with this call :
编译器不能停止抱怨这个电话：
EasyMock.anyObject(List.class)
I tried to specify list's type
我试图指定列表的类型
EasyMock.anyObject(List<MyType>.class)
but it doesn't seems to be an option (anyway, it is stupid since java will erase the type during the compilation)
但它似乎不是一个选项（无论如何，这是愚蠢的，因为java会在编译期间擦除类型）
Is there a clean way (@SuppressWarning is not a clean way IMO) to remove this warning?
有没有干净的方法（@SuppressWarning 不是 IMO 的干净方法）来删除此警告？
Thank you
谢谢
回答by Henri Tremblay
It's not possible. I'll call it a generic limitation. Sadly it's not always possible to remove a warning for some perfectly normal usage (like using the class of a generic class).
这是不可能的。我将其称为通用限制。遗憾的是，对于某些完全正常的使用（例如使用泛型类的类），并不总是可以删除警告。
However, with EasyMock you can do the following:
但是，使用 EasyMock，您可以执行以下操作：
EasyMock.<List<MyType>> anyObject()
which will do the same thing but without warning. The anyObject you used exist because it's a bit more readable and allows static imports.
这将做同样的事情，但没有警告。您使用的 anyObject 存在是因为它更具可读性并且允许静态导入。
回答by Stan Kurilin
Only as suggestion :
仅作为建议：
interface A extends List<MyType> {};
EasyMock.anyObject(A.class)
回答by A. Mazur
You can also try to use the Hamcrest matcher isA(), instead of anyObject(). The difference between them is that isA-matcher checks the values on null, unlike anyObject.
You can learn more about those matchers here
您也可以尝试使用 Hamcrest 匹配器isA()，而不是anyObject(). 它们之间的区别在于isA-matcher 检查 上的值null，与anyObject. 您可以在此处了解有关这些匹配器的更多信息
