C# 使用 XmlDocument 读取 XML 属性
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Read XML Attribute using XmlDocument
提问by Alex
How can I read an XML attribute using C#'s XmlDocument?
如何使用 C# 的 XmlDocument 读取 XML 属性？
I have an XML file which looks somewhat like this:
我有一个看起来像这样的 XML 文件：
<?xml version="1.0" encoding="utf-8" ?>
<MyConfiguration xmlns="http://tempuri.org/myOwnSchema.xsd" SuperNumber="1" SuperString="whipcream">
<Other stuff />
</MyConfiguration>
How would I read the XML attributes SuperNumber and SuperString?
我将如何读取 XML 属性 SuperNumber 和 SuperString？
Currently I'm using XmlDocument, and I get the values in between using XmlDocument's GetElementsByTagName()and that works really well. I just can't figure out how to get the attributes?
目前我正在使用 XmlDocument，并且我使用 XmlDocument 获得了介于两者之间的值，GetElementsByTagName()并且效果非常好。我就是不知道如何获得属性？
采纳答案by Arsen Mkrtchyan
XmlNodeList elemList = doc.GetElementsByTagName(...);
for (int i = 0; i < elemList.Count; i++)
{
string attrVal = elemList[i].Attributes["SuperString"].Value;
}
回答by jerryjvl
XmlDocument.Attributesperhaps? (Which has a method GetNamedItem that will presumably do what you want, although I've always just iterated the attribute collection)
XmlDocument.Attributes也许？（它有一个方法 GetNamedItem 大概可以做你想做的事，虽然我一直只是迭代属性集合）
回答by Greg
You should look into XPath. Once you start using it, you'll find its a lot more efficient and easier to code than iterating through lists. It also lets you directly get the things you want.
您应该查看XPath。一旦你开始使用它，你会发现它比遍历列表更高效、更容易编写代码。它还可以让您直接获得您想要的东西。
Then the code would be something similar to
然后代码将类似于
string attrVal = doc.SelectSingleNode("/MyConfiguration/@SuperNumber").Value;
Note that XPath 3.0 became a W3C Recommendation on April 8, 2014.
请注意，XPath 3.0 于 2014 年 4 月 8 日成为 W3C 推荐标准。
回答by Matt Sherman
You can migrate to XDocument instead of XmlDocument and then use Linq if you prefer that syntax. Something like:
如果您喜欢这种语法，您可以迁移到 XDocument 而不是 XmlDocument，然后使用 Linq。就像是：
var q = (from myConfig in xDoc.Elements("MyConfiguration")
select myConfig.Attribute("SuperString").Value)
.First();
回答by siva
I have an Xml File books.xml
我有一个 Xml 文件 books.xml
<ParameterDBConfig>
<ID Definition="1" />
</ParameterDBConfig>
Program:
程序：
XmlDocument doc = new XmlDocument();
doc.Load("D:/siva/books.xml");
XmlNodeList elemList = doc.GetElementsByTagName("ID");
for (int i = 0; i < elemList.Count; i++)
{
string attrVal = elemList[i].Attributes["Definition"].Value;
}
Now, attrValhas the value of ID.
现在，attrVal具有 的值ID。
回答by Colonel Panic
Assuming your example document is in the string variable doc
假设您的示例文档在字符串变量中 doc
> XDocument.Parse(doc).Root.Attribute("SuperNumber")
1
回答by Voicu
If your XML contains namespaces, then you can do the following in order to obtain the value of an attribute:
如果您的 XML 包含命名空间，那么您可以执行以下操作以获得属性的值：
var xmlDoc = new XmlDocument();
// content is your XML as string
xmlDoc.LoadXml(content);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(new NameTable());
// make sure the namespace identifier, URN in this case, matches what you have in your XML
nsmgr.AddNamespace("ns", "urn:oasis:names:tc:SAML:2.0:protocol");
// get the value of Destination attribute from within the Response node with a prefix who's identifier is "urn:oasis:names:tc:SAML:2.0:protocol" using XPath
var str = xmlDoc.SelectSingleNode("/ns:Response/@Destination", nsmgr);
if (str != null)
{
Console.WriteLine(str.Value);
}
