PHP 动态包含基于当前文件路径
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2617931/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
PHP Dynamic include based on current file path
提问by Adrian M.
I want to find a method to include some files based on the current file path.. for example:
我想找到一种方法来包含基于当前文件路径的一些文件.. 例如：
I have "website.com/templates/name1/index.php", this "index.php should be a unique file that I will use in many different directories on different depths, so I want to make the code universal so I don't need to change anything inside this file..
我有“website.com/templates/name1/index.php”，这个“index.php 应该是一个唯一的文件，我将在不同深度的许多不同目录中使用它，所以我想让代码通用，所以我不这样做”不需要更改此文件中的任何内容..
So if this "index.php" is located in
所以如果这个“index.php”位于
"website.com/templates/name1/index.php"
“ website.com/templates/name1/index.php”
than it should include the file located here:
它应该包含位于此处的文件：
"website.com/content/templates/name1/content.php"
“ website.com/content/templates/name1/content.php”
another example:
另一个例子：
"website.com/templates/name2/index.php"
“ website.com/templates/name2/index.php”
than it should include the file located here:
它应该包含位于此处的文件：
"website.com/content/templates/name2/content.php"
“ website.com/content/templates/name2/content.php”
Also I want to overrun "Warning: include_once() [function.include-once]: http:// wrapper is disabled in the server configuration by allow_url_include=0" kind of error.. because is disabled and unsafe..
另外我想超出“警告：include_once() [function.include-once]：http://wrapper is disabled in the server configuration by allow_url_include=0”类型的错误..因为被禁用且不安全..
Is there a way to achieve this? Thank you!
有没有办法实现这一目标？谢谢！
回答by Sergey Kuznetsov
I think you need to use __FILE__(it has two underscores at the start and at the end of the name) and DIRECTORY_SEPARATORconstants for working with files based on the current file path.
我认为您需要使用__FILE__（它在名称的开头和结尾有两个下划线）和DIRECTORY_SEPARATOR常量来处理基于当前文件路径的文件。
For example:
例如：
<?php
// in this var you will get the absolute file path of the current file
$current_file_path = dirname(__FILE__);
// with the next line we will include the 'somefile.php'
// which based in the upper directory to the current path
include(dirname(__FILE__) . DIRECTORY_SEPARATOR . '..' . DIRECTORY_SEPARATOR . 'somefile.php');
Using DIRECTORY_SEPARATORconstant is more safe than using "/"(or "\") symbols, because Windows and *nix directory separators are different and your interpretator will use proper value on the different platforms.
使用DIRECTORY_SEPARATOR常量比使用“/”（或“\”）符号更安全，因为 Windows 和 *nix 目录分隔符是不同的，您的解释器将在不同平台上使用正确的值。
回答by vignesh
<?php
if (isset($_GET['service'])) {
include('subContent/serviceMenu.html');
} else if (isset($_GET['business'])) {
include('subContent/business_menu.html');
} else if (isset($_GET['info'])) {
include('subContent/info_menu.html');
}
else {
include('subContent/banner.html');
}
?>
<a href="http://localhost/yourpage.php?service" />
回答by Rasmus
I'd just do something as simple as:
我只会做一些简单的事情：
$dir = str_replace('website.com/','website.com/content/',__DIR__);
include "$dir/content.php";
And your HTTP wrapper issue doesn't seem to have anything to do with this. What do you mean by overrun it? You generally never want to do a remote include.
而您的 HTTP 包装器问题似乎与此无关。超过它是什么意思？您通常永远不想进行远程包含。
回答by Ashesh Ambasta
Why not do it in the simple way:
为什么不以简单的方式做到这一点：
dirname(__FILE__); //Current working directory
dirname(dirname(__FILE__)); //Get path to current working directory
And then finally
然后最后
$include_path = $dir_path . 'file_to_include.php';
include $include_path;
