Laravel v5.2.* (v5.2.29) Auth::guard('api')->attempt($user) 致命错误
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Laravel v5.2.* (v5.2.29) Auth::guard('api')->attempt($user) fatal error
提问by Vanya Avchyan
Has anyone encountered this problem
有没有人遇到过这个问题
dd($this->user->check()); return false
but
但
Auth::guard('user')->attempt(App\User::find(1))
return the error
返回错误
Call to undefined method Illuminate\Auth\TokenGuard::attempt()
调用未定义的方法 Illuminate\Auth\TokenGuard::attempt()
Please help to resolve this problem.
请帮助解决这个问题。
回答by Vanya Avchyan
I solved this problem
我解决了这个问题
In config/auth.phpconfiguration:
在config/auth.php配置中：
'user' => [
'driver' => 'token',
'provider' => 'userProvider',
],
We need to change to:
我们需要改为：
'user' => [
'driver' => 'session',
'provider' => 'userProvider',
],
Because Auth::guarddata is stored in the session
因为Auth::guard数据存储在会话中
And further work on the well-known scheme
以及对众所周知的方案的进一步工作
Auth::login() = Auth::guard('user')->login()
Auth::attempt() = Auth::guard('user')->attempt()
Auth::user() = Auth::guard('user')->user()
...
回答by MikielD.
To the function attemptyou shall pass an array of creditianals, not a user object.
attempt您应该向该函数传递一个creditianals 数组，而不是一个用户对象。
For example:
例如：
Auth::guard('user')->attempt([
'email' => '[email protected]',
'password' => '1234'
]);
And if you are using Laravel and need to authenticate the user, you can call similar:
如果您正在使用 Laravel 并且需要对用户进行身份验证，您可以调用类似的方法：
auth()->attempt([
'email' => '[email protected]',
'password' => '1234'
]);
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