将 Java 对象转换为 XML 字符串

Convert Java object to XML string

提问by Bob

Yes, yes I know that lots of questions were asked about this topic. But I still cannot find the solution to my problem. I have a property annotated Java object. For example Customer, like in this example. And I want a String representation of it. Google reccomends using JAXB for such purposes. But in all examples created XML file is printed to file or console, like this:

是的，是的，我知道有很多关于这个话题的问题。但我仍然找不到解决我的问题的方法。我有一个带有属性注释的 Java 对象。例如客户，就像在这个例子中一样。我想要它的字符串表示。Google 建议将 JAXB 用于此类目的。但在所有示例中，创建的 XML 文件都会打印到文件或控制台，如下所示：

File file = new File("C:\file.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

// output pretty printed
jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

jaxbMarshaller.marshal(customer, file);
jaxbMarshaller.marshal(customer, System.out);

But I have to use this object and send over network in XML format. So I want to get a String which represents XML.

但我必须使用这个对象并以 XML 格式通过网络发送。所以我想得到一个代表 XML 的字符串。

String xmlString = ...
sendOverNetwork(xmlString);

How can I do this?

我怎样才能做到这一点？

采纳答案by A4L

You can use the Marshaler's method for marshaling which takes a Writeras parameter:

您可以使用 Marshaler 的方法进行封送处理，该方法以Writer作为参数：

marshal(Object,Writer)

元帅（对象，作家）

and pass it an Implementation which can build a String object

并传递一个可以构建 String 对象的实现

Direct Known Subclasses:BufferedWriter, CharArrayWriter, FilterWriter, OutputStreamWriter, PipedWriter, PrintWriter, StringWriter

直接已知子类：BufferedWriter、CharArrayWriter、FilterWriter、OutputStreamWriter、PipedWriter、PrintWriter、StringWriter

Call its toStringmethod to get the actual String value.

调用它的toString方法来获取实际的 String 值。

So doing:

这样做：

StringWriter sw = new StringWriter();
jaxbMarshaller.marshal(customer, sw);
String xmlString = sw.toString();

回答by SLaks

You can marshal it to a StringWriterand grab its string. from toString().

你可以将它编组到 aStringWriter并抓住它的字符串。从toString().

回答by Surendra

As A4L mentioning, you can use StringWriter. Providing here example code:

正如 A4L 所提到的，您可以使用 StringWriter。在此处提供示例代码：

private static String jaxbObjectToXML(Customer customer) {
    String xmlString = "";
    try {
        JAXBContext context = JAXBContext.newInstance(Customer.class);
        Marshaller m = context.createMarshaller();

        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); // To format XML

        StringWriter sw = new StringWriter();
        m.marshal(customer, sw);
        xmlString = sw.toString();

    } catch (JAXBException e) {
        e.printStackTrace();
    }

    return xmlString;
}

回答by Rahul Raina

Testing And working Java code to convert java object to XML:

将 Java 对象转换为 XML 的测试和工作 Java 代码：

Customer.java

客户.java

import java.util.ArrayList;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;


@XmlRootElement
public class Customer {

    String name;
    int age;
    int id;
    String desc;
    ArrayList<String> list;

    public ArrayList<String> getList()
    {
        return list;
    }

    @XmlElement
    public void setList(ArrayList<String> list)
    {
        this.list = list;
    }

    public String getDesc()
    {
        return desc;
    }

    @XmlElement
    public void setDesc(String desc)
    {
        this.desc = desc;
    }

    public String getName() {
        return name;
    }

    @XmlElement
    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    @XmlElement
    public void setAge(int age) {
        this.age = age;
    }

    public int getId() {
        return id;
    }

    @XmlAttribute
    public void setId(int id) {
        this.id = id;
    }
}

createXML.java

创建XML文件

import java.io.StringWriter;
import java.util.ArrayList;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;


public class createXML {

    public static void main(String args[]) throws Exception
    {
        ArrayList<String> list = new ArrayList<String>();
        list.add("1");
        list.add("2");
        list.add("3");
        list.add("4");
        Customer c = new Customer();
        c.setAge(45);
        c.setDesc("some desc ");
        c.setId(23);
        c.setList(list);
        c.setName("name");
        JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        StringWriter sw = new StringWriter();
        jaxbMarshaller.marshal(c, sw);
        String xmlString = sw.toString();
        System.out.println(xmlString);
    }

}

回答by Abu Bakar Siddik

To convert an Object to XML in Java

在 Java 中将对象转换为 XML

Customer.java

客户.java

package com;

import java.util.ArrayList;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

/**
*
* @author ABsiddik
*/

@XmlRootElement
public class Customer {

int id;
String name;
int age;

String address;
ArrayList<String> mobileNo;


 public int getId() {
    return id;
}

@XmlAttribute
public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

@XmlElement
public void setName(String name) {
    this.name = name;
}

public int getAge() {
    return age;
}

@XmlElement
public void setAge(int age) {
    this.age = age;
}

public String getAddress() {
    return address;
}

@XmlElement
public void setAddress(String address) {
    this.address = address;
}

public ArrayList<String> getMobileNo() {
    return mobileNo;
}

@XmlElement
public void setMobileNo(ArrayList<String> mobileNo) {
    this.mobileNo = mobileNo;
}


}

ConvertObjToXML.java

ConvertObjToXML.java

package com;

import java.io.File;
import java.io.StringWriter;
import java.util.ArrayList;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

/**
*
* @author ABsiddik
*/
public class ConvertObjToXML {

public static void main(String args[]) throws Exception
{
    ArrayList<String> numberList = new ArrayList<>();
    numberList.add("01942652579");
    numberList.add("01762752801");
    numberList.add("8800545");

    Customer c = new Customer();

    c.setId(23);
    c.setName("Abu Bakar Siddik");
    c.setAge(45);
    c.setAddress("Dhaka, Bangladesh");
    c.setMobileNo(numberList);

    File file = new File("C:\Users\NETIZEN-ONE\Desktop \customer.xml");
    JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    jaxbMarshaller.marshal(c, file);// this line create customer.xml file in specified path.

    StringWriter sw = new StringWriter();
    jaxbMarshaller.marshal(c, sw);
    String xmlString = sw.toString();

    System.out.println(xmlString);
}

}

Try with this example..

试试这个例子..

回答by Sireesh Yarlagadda

Using ByteArrayOutputStream

使用 ByteArrayOutputStream

public static String printObjectToXML(final Object object) throws TransformerFactoryConfigurationError,
        TransformerConfigurationException, SOAPException, TransformerException
{
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    XMLEncoder xmlEncoder = new XMLEncoder(baos);
    xmlEncoder.writeObject(object);
    xmlEncoder.close();

    String xml = baos.toString();
    System.out.println(xml);

    return xml.toString();
}

回答by Abhay Gupta

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;

private String generateXml(Object obj, Class objClass) throws JAXBException {
        JAXBContext jaxbContext = JAXBContext.newInstance(objClass);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        StringWriter sw = new StringWriter();
        jaxbMarshaller.marshal(obj, sw);
        return sw.toString();
    }

回答by juliaaano

A convenient option is to use javax.xml.bind.JAXB:

一个方便的选择是使用javax.xml.bind.JAXB：

StringWriter sw = new StringWriter();
JAXB.marshal(customer, sw);
String xmlString = sw.toString();

The reverse process (unmarshal) would be:

反向过程（解组）将是：

Customer customer = JAXB.unmarshal(new StringReader(xmlString), Customer.class);

No need to deal with checked exceptions in this approach.

这种方法不需要处理检查异常。

回答by K. Soni

Use this function to convert Object to xml string (should be called as convertToXml(sourceObject, Object.class); )-->

使用这个函数将Object转换成xml字符串（应该叫convertToXml(sourceObject, Object.class);）-->

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.namespace.QName;

public static <T> String convertToXml(T source, Class<T> clazz) throws JAXBException {
    String result;
    StringWriter sw = new StringWriter();
    JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
    Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
    jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
    QName qName = new QName(StringUtils.uncapitalize(clazz.getSimpleName()));
    JAXBElement<T> root = new JAXBElement<T>(qName, clazz, source);
    jaxbMarshaller.marshal(root, sw);
    result = sw.toString();
    return result;
}

Use this function to convert xml string to Object back --> (should be called as createObjectFromXmlString(xmlString, Object.class))

使用该函数将xml字符串转回Object-->（应调用为createObjectFromXmlString(xmlString, Object.class)）

public static <T> T createObjectFromXmlString(String xml, Class<T> clazz) throws JAXBException, IOException{

    T value = null;
    StringReader reader = new StringReader(xml); 
    JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
    Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
    JAXBElement<T> rootElement=jaxbUnmarshaller.unmarshal(new StreamSource(reader),clazz);
    value = rootElement.getValue();
    return value;
}

回答by Vasudeva Krishnan

Some Generic code to create XML Stirng

创建 XML 搅拌的一些通用代码

object --> is Java class to convert it to XML
name --> is just name space like thing - for differentiate

object --> 是将其转换为 XML名称的Java 类
--> 只是名称空间之类的东西 - 用于区分

public static String convertObjectToXML(Object object,String name) {
          try {
              StringWriter stringWriter = new StringWriter();
              JAXBContext jaxbContext = JAXBContext.newInstance(object.getClass());
              Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
              jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
              QName qName = new QName(object.getClass().toString(), name);
              Object root = new JAXBElement<Object>(qName,java.lang.Object.class, object);
              jaxbMarshaller.marshal(root, stringWriter);
              String result = stringWriter.toString();
              System.out.println(result);
              return result;
        }catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }