jQuery 未捕获的类型错误：无法调用未定义的方法“拆分”
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Uncaught TypeError: Cannot call method 'split' of undefined
提问by humanbeing
I'm trying to include on my website the Quicksand script, but I failed badly.
Firebug gives me this error: 65 Uncaught TypeError: Cannot call method 'split' of undefined:
我试图在我的网站上包含 Quicksand 脚本，但我失败了。
Firebug 给了我这个错误65 Uncaught TypeError: Cannot call method 'split' of undefined：
for this script:
对于这个脚本：
jQuery.noConflict();
jQuery(document).ready(function($){
// Clone applications to get a second collection
var $data = $("#portfolio-items").clone();
//NOTE: Only filter on the main portfolio page, not on the subcategory pages
$('#portfolio-terms ul li').click(function(e) {
$("ul li").removeClass("active");
// Use the last category class as the category to filter by. This means that multiple categories are not supported (yet)
var filterClass=$(this).attr('class').split(' ').slice(-1)[0];
jquery.custom.js:65 Uncaught TypeError: Cannot call method 'split' of undefined (repeated 6 times)
if (filterClass == '.all current') {
var $filteredData = $data.find('#portfolio-');
} else {
var $filteredData = $data.find('#portfolio-[data-type=' + filterClass + ']');
}
$("#portfolio-items").quicksand($filteredData, {
duration: 800,
easing: 'swing',
});
$(this).addClass("active");
return false;
});
});
See here: http://stakk.it/
what is the error?
thank you and sorry for my bad english!
请参阅此处：http: //stakk.it/
错误是什么？
谢谢你，对不起我的英语不好！
回答by Kevin B
If .attr("class")returns undefined, you can't call .spliton it because .splitis a method of the Stringobject and can't be called on undefined. You need to store the result of .attr("class")and then only split it if it is not undefined.
如果.attr("class")返回undefined，则不能调用.split它，因为它.split是String对象的方法并且不能被调用undefined。您需要存储 的结果，.attr("class")如果不是，则仅将其拆分undefined。
var filterClass = $(this).attr('class');
filterClass = filterClass ? filterClass.split(' ').slice(-1)[0] : '';
now filterClass will contain what you expect, or an empty string.
现在 filterClass 将包含您期望的内容，或一个空字符串。
Edit: you could replace $(this).attr('class')with this.className, pulled from removed answer.
编辑：您可以替换$(this).attr('class')为this.className, 从已删除的答案中拉出。
回答by Yuseferi
Another solution is using toStringmethod
另一种解决方案是使用toString方法
var filterClass = $(this).attr('class').toString();
filterClass = filterClass.split(' ');
it worked for me
它对我有用
