如何从 C# 中的 JSON 字符串中获取一些值？
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How to get some values from a JSON string in C#?
提问by Alon Shmiel
I have a string and I want to get some values from it.
我有一个字符串，我想从中获取一些值。
My strings seem like:
我的字符串看起来像：
string1:
字符串 1：
"{\r\n \"id\": \"100000280905615\",
\r\n \"name\": \"Jerard Jones\",
\r\n \"first_name\": \"Jerard\",
\r\n \"last_name\": \"Jones\",
\r\n \"link\": \"https://www.facebook.com/Jerard.Jones\",
\r\n \"username\": \"Jerard.Jones\",
\r\n \"gender\": \"female\",
\r\n \"locale\": \"en_US\"\r\n}"
string2:
字符串2：
"{\r\n \"id\": \"100000390001929\",
\r\n \"name\": \"\u05d1\u05d2\u05e8\u15dc\u25d9 \u05d1\u05e8\u05d5\u05e9\",
\r\n \"first_name\": \"\u05d4\u05d2\u05e7\u02dc\u05d9\",
\r\n \"last_name\": \"\u05d1\u05e8\u05d5\u05e9\",
\r\n \"link\": "https://www.facebook.com/people/\u05d2\u05d1\u05e@\u05dc\u05d9-\u05d1\u05e8\u05d4\u05e9/100000390001929\",
\r\n \"gender\": \"female\",
\r\n \"locale\": \"he_IL\"\r\n}"
Unfortunately, there is a situation that a string will be by the same concept, but without some parameters:
不幸的是，有一种情况是字符串将具有相同的概念，但没有一些参数：
string3:
字符串 3：
"{\r\n \"id\": \"100000390001929\",
\r\n \"last_name\": \"\u05d1\u05e8\u05d5\u05e9\",
\r\n \"gender\": \"female\",
\r\n \"locale\": \"he_IL\"\r\n}"
How can I get the values of: id, first_name, last_name, gender, locale?
如何获得以下值：id, first_name, last_name, gender, locale？
Any help appreciated!
任何帮助表示赞赏！
采纳答案by Rubens Mariuzzo
Your strings are JSON formatted, so you will need to parse itinto a object. For that you can use JSON.NET.
您的字符串是 JSON 格式的，因此您需要将其解析为一个对象。为此，您可以使用JSON.NET。
Here is an example on how to parse a JSON string into a dynamic object:
下面是一个关于如何将 JSON 字符串解析为动态对象的示例：
string source = "{\r\n \"id\": \"100000280905615\", \r\n \"name\": \"Jerard Jones\", \r\n \"first_name\": \"Jerard\", \r\n \"last_name\": \"Jones\", \r\n \"link\": \"https://www.facebook.com/Jerard.Jones\", \r\n \"username\": \"Jerard.Jones\", \r\n \"gender\": \"female\", \r\n \"locale\": \"en_US\"\r\n}";
dynamic data = JObject.Parse(source);
Console.WriteLine(data.id);
Console.WriteLine(data.first_name);
Console.WriteLine(data.last_name);
Console.WriteLine(data.gender);
Console.WriteLine(data.locale);
Happy coding!
快乐编码！
回答by Ligabb
Create a class like this:
创建一个这样的类：
public class Data
{
public string Id {get; set;}
public string Name {get; set;}
public string First_Name {get; set;}
public string Last_Name {get; set;}
public string Username {get; set;}
public string Gender {get; set;}
public string Locale {get; set;}
}
(I'm not 100% sure, but if that doesn't work you'll need use [DataContract]and [DataMember]for DataContractJsonSerializer.)
（我不是 100% 确定，但如果这不起作用，您将需要使用[DataContract]and [DataMember]for DataContractJsonSerializer。）
Then create JSonSerializer:
然后创建JSonSerializer：
private static readonly XmlObjectSerializer Serializer = new DataContractJsonSerializer(typeof(Data));
and deserialize object:
并反序列化对象：
// convert string to stream
byte[] byteArray = Encoding.UTF8.GetBytes(contents);
using(var stream = new MemoryStream(byteArray))
{
(Data)Serializer.ReadObject(stream);
}
回答by Muhammad Awais
Following code is working for me.
以下代码对我有用。
Usings:
用途：
using System.IO;
using System.Net;
using Newtonsoft.Json.Linq;
Code:
代码：
using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
{
using (Stream responseStream = response.GetResponseStream())
{
using (StreamReader responseReader = new StreamReader(responseStream))
{
string json = responseReader.ReadToEnd();
string data = JObject.Parse(json)["id"].ToString();
}
}
}
//json = {"kind": "ALL", "id": "1221455", "longUrl": "NewURL"}
回答by DKR
my string
我的字符串
var obj = {"Status":0,"Data":{"guid":"","invitationGuid":"","entityGuid":"387E22AD69-4910-430C-AC16-8044EE4A6B24443545DD"},"Extension":null}
Following code to get guid:
以下代码获取 guid：
var userObj = JObject.Parse(obj);
var userGuid = Convert.ToString(userObj["Data"]["guid"]);
