javascript Angular ng-options 删除空白选项并仅选择第一个选项
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Angular ng-options remove blank option and select the first option only
提问by Ankit Tanna
I am using AngularJS to populate my select options content dynamically from an array of objects in my controller. My objects has a property named userProfileName.
我正在使用 AngularJS 从控制器中的对象数组动态填充我的选择选项内容。我的对象有一个名为userProfileName的属性。
How would it be possible to remove the blank option that I am getting at the top?
怎么可能删除我在顶部得到的空白选项?
Also, I would want to select the first profile Profile 1by default. How can this be done?
另外,我想默认选择第一个配置文件Profile 1。如何才能做到这一点?
My Snippet of code is here:
我的代码片段在这里:
<select id="requestorSite"
ng-model="selectedUserProfile"
ng-options="userProfile.userProfileName for userProfile in userProfiles"
ng-selected=""
class="form-control displayInlineBlock width40per marginLeft15">
</select>
My controller has
我的控制器有
$scope.userProfiles
As the array of object and each object has userProfileNameattribute.
作为对象数组,每个对象都有userProfileName属性。
Below is the screen shot:
下面是屏幕截图:
I would like to remove the blank option at the top and also have by default Profile 1selected.
我想删除顶部的空白选项,并默认选择配置文件 1。
Thanks, Ankit
谢谢,安吉特
回答by carton
Do this :)
做这个 :)
In your controller :
在您的控制器中:
function myCtrl ($scope) {
$scope.userProfiles = [
{id: 10, name: 'Carton'},
{id: 27, name: 'Bernard'},
{id: 39, name: 'Julie'},
];
$scope.selectedUserProfile= $scope.userProfiles[0]; // Set by default the value "carton"
};
In your page :
在您的页面中:
<select id="requestorSite" ng-model="selectedUserProfile" ng-options="userProfile as userProfile.name for userProfile in userProfiles">
</select>
CodePen: http://codepen.io/anon/pen/qdOGVB
代码笔:http://codepen.io/anon/pen/qdOGVB
回答by Hari Das
This has several solution. The following worked best for me. Just initialize the model with the first value. The ng-init="myItem = items[0].name"
does the trick
这有几个解决办法。以下对我来说效果最好。只需使用第一个值初始化模型。该ng-init="myItem = items[0].name"
做的伎俩
<select ng-if="items" ng-init="myItem = items[0].name" ng-model="myItem">
<option ng-repeat="item in items" ng-value="item.name">{{item.name}}</option>
</select>