如何从android中的字符串创建UUID
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How to create UUID from string in android
提问by user3056760
In my app, I scan low energy Bluetooth for specific service uuid 2415. To convert the string 2415 into uuid I am using UUID serviceUUID = UUID.fromString("2415");but at this line exception arises IllegalArgumentException: Invalid UUID 2415.
在我的应用程序中，我扫描低功耗蓝牙以获取特定服务 uuid 2415。要将字符串 2415 转换为我正在使用的 uuid，UUID serviceUUID = UUID.fromString("2415");但在这一行出现异常 IllegalArgumentException: Invalid UUID 2415。
Please help me in this respect I would b very thankful to in this regard. Thanks in advance.
请在这方面帮助我，我将在这方面非常感谢。提前致谢。
回答by Alécio Carvalho
回答by Richard Le Mesurier
The accepted answer was provided in a comment by @Michael:
接受的答案在@Michael 的评论中提供：
Have you tried combining your short UUID with the Bluetooth base UUID? I.e. "00002415-0000-1000-8000-00805F9B34FB"? (assuming that you meant 2415 hexadecimal)?
您是否尝试过将短 UUID 与蓝牙基础 UUID 结合使用？即“00002415-0000-1000-8000-00805F9B34FB”？（假设你的意思是 2415 十六进制）？
I'm converting that comment to an answer because I missed it first time I read through this thread.
我正在将该评论转换为答案，因为我第一次阅读此线程时错过了它。
回答by ?zer ?zcan
you can use
您可以使用
String str = "1234";
UUID uuid = UUID.nameUUIDFromBytes(str.getBytes());
System.out.print(uuid.toString());
回答by 92tonywills
The confusion that may lead many people here is that you can use short code UUIDs to reference bluetooth services and characteristics on other platforms - for instance on iOS with CBUUID. On Android however, you must provide a full, 128-bit length UUID as specified in RFC4122.
这里可能会导致很多人感到困惑的是，您可以使用短代码 UUID 来引用其他平台上的蓝牙服务和特性 - 例如在带有CBUUID 的iOS 上。但是，在 Android 上，您必须提供RFC4122 中指定的完整的 128 位长度的 UUID 。
The fix (as @Michael pointed out) is to prepend your 16bit or 32bit short UUID to the base bluetooth UUID. You can use these functions to make this a bit easier.
修复（如@Michael 指出的）是将您的 16 位或 32 位短 UUID 附加到基本蓝牙 UUID。您可以使用这些功能使这更容易一些。
public static final String baseBluetoothUuidPostfix = "0000-1000-8000-00805F9B34FB";
public static UUID uuidFromShortCode16(String shortCode16) {
return UUID.fromString("0000" + shortCode16 + "-" + baseBluetoothUuidPostfix);
}
public static UUID uuidFromShortCode32(String shortCode32) {
return UUID.fromString(shortCode32 + "-" + baseBluetoothUuidPostfix);
}
For example:
例如：
UUID uuid = uuidFromShortCode16("FFF0");
This creates a UUID object from "0000FFF0-0000-1000-8000-00805F9B34FB".
这将创建一个 UUID 对象"0000FFF0-0000-1000-8000-00805F9B34FB"。
回答by Akhilesh Kumar
Hope this will help
The exception is due to invalid argument in UUID.fromString()method.
The UUID.fromString()method expect "302a5a70-c085-4946-b702-fc1deb1046af"type of string as its argument and returns instance of UUIDclass.
To Convert short hand 16-bit uuid to 128 bit uuid you can use this template "0000XXXX-0000-1000-8000-00805F9B34FB". here replace XXXXwith your 16 bit uuid.
For example:
In your use case 128 bit UUID will be "00002415-0000-1000-8000-00805F9B34FB".
and to get UUID from string you should use code like this UUID uuid = UUID.fromString("00002415-0000-1000-8000-00805F9B34FB");
https://newcircle.com/s/post/1786/2016/01/04/bluetooth-uuids-and-interoperable-advertisements
希望这会有所帮助
异常是由于UUID.fromString()方法中的无效参数。
该UUID.fromString()方法期望"302a5a70-c085-4946-b702-fc1deb1046af"字符串类型作为其参数并返回UUID类的实例。
要将简写 16 位 uuid 转换为 128 位 uuid，您可以使用此模板"0000XXXX-0000-1000-8000-00805F9B34FB"。此处替换XXXX为您的 16 位 uuid。
例如：
在您的用例中，128 位 UUID 将是"00002415-0000-1000-8000-00805F9B34FB".
并从字符串中获取 UUID，您应该使用这样的代码UUID uuid = UUID.fromString("00002415-0000-1000-8000-00805F9B34FB");
https://newcircle.com/s/post/1786/2016/01/04/bluetooth-uuids-and-interoperable-advertisements
回答by bremen_matt
I have a feeling that your String "2415" might just have been straight-up converted from a long, because, as the others point out, "2415" is not close to resembling a UUID. If that is the case, then you should use the UUID constructor which takes two longs:
我有一种感觉，您的字符串“2415”可能只是从 long 直接转换而来，因为正如其他人指出的那样，“2415”与 UUID 不太相似。如果是这种情况，那么您应该使用带有两个 long 的 UUID 构造函数：
uuid = new UUID(long mostSignificant, long leastSignificant)
uuid = new UUID(long mostSignificant, long leastSignificant)
where you can retrieve those long values via
您可以通过以下方式检索这些长值
uuid.getMostSignificantBits()uuid.getLeastSignificantBits()
uuid.getMostSignificantBits()uuid.getLeastSignificantBits()
So in your case, you might do something like uuid = new UUID(2415,2415)
所以在你的情况下，你可能会做类似的事情 uuid = new UUID(2415,2415)
