删除java中的空格和特殊字符
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/22936009/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Remove white space and special characters in java
提问by Devendra
I have String which contains some special characters and white spaces as well.I want to remove white spaces and special character I am doing it as
我有包含一些特殊字符和空格的字符串。我想删除空格和特殊字符我正在这样做
String str = "45,%$^ Sharma%$&^,is,46&* a$# java# Developer$#$^ in#$^ CST&^* web*&(,but He%^&^% want to move@!$@# in another team";
System.out.println( str.replaceAll("[^a-zA-Z]", " ").replaceAll("\s+"," "));
Output :- sharma is a java Developer in CST web but He want to move in another team
Can i do this using single operation? how?
我可以使用单个操作来做到这一点吗？如何？
采纳答案by Cephalopod
Replace any sequence of non-letters with a single whitespace:
用一个空格替换任何非字母序列：
str.replaceAll("[^a-zA-Z]+", " ")
You also might want to apply trim()after the replace.
您可能还想trim()在更换后申请。
If you want to support languages other than english, use "[^\\p{IsAlphabetic}]+"or "[^\\p{IsLetter}]+". See this questionabout the differences.
如果您想支持英语以外的语言，请使用"[^\\p{IsAlphabetic}]+"或"[^\\p{IsLetter}]+"。请参阅有关差异的问题。
回答by Sabuj Hassan
Try this:
尝试这个：
str.replaceAll("[\p{Punct}\s\d]+", " ");
Replacing punctuation, digits and white spaces with a single space.
用一个空格替换标点符号、数字和空格。
回答by TomasZ.
The OR operator | should work:
OR 运算符 | 应该管用：
System.out.println(str.replaceAll("([^a-zA-Z]|\s)+", " "));
Actually, the space doesn't have to be there at all:
实际上，空间根本不必在那里：
System.out.println(str.replaceAll("[^a-zA-Z]+", " "));
回答by Al-Mustafa Azhari
You can use below to remove anything that is not a character (A-Z or a-z) .
您可以使用下面删除任何不是字符 (AZ 或 az) 的内容。
str.replaceAll("[^a-zA-Z]","");
