javascript JSON.parse 给出了一个“未定义”的对象
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JSON.parse is giving an "undefined" object
提问by richerlariviere
I tried to parse this string :
我试图解析这个字符串：
[{"ZoneId": "1", "0": "1", "ZoneX": "29", "1": "29", "ZoneY": "27", "2": "27", "ZoneWidth": "76", "3": "76", "ZoneHeight": "61", "4": "61", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"},
{"ZoneId": "2", "0": "2", "ZoneX": "382", "1": "382", "ZoneY": "226", "2": "226", "ZoneWidth": "-117", "3": "-117", "ZoneHeight": "98", "4": "98", "ZoneImage": "46", "5": "46", "ZonePointTo": "3", "6": "3"},
{"ZoneId": "3", "0": "3", "ZoneX": "108", "1": "108", "ZoneY": "74", "2": "74", "ZoneWidth": "363", "3": "363", "ZoneHeight": "83", "4": "83", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"}]
Using JSON.parse() on this string show me "undefined" in the console. According to this site, my json is valid. It comes from a json_encode given by a php function.
在此字符串上使用 JSON.parse() 在控制台中显示“未定义”。根据这个站点，我的 json 是有效的。它来自 php 函数给出的 json_encode。
If it can help, the final goal is to loop through this json array. Thanks.
如果有帮助，最终目标是遍历这个 json 数组。谢谢。
[EDIT]
[编辑]
I realized that my error was in fact a scope issue using literal functions. Yes, I'm a bit stupid sometimes. Thanks everybody for your help!
我意识到我的错误实际上是使用文字函数的范围问题。是的，我有时有点傻。感谢大家的帮助！
采纳答案by Marvin Emil Brach
This is no String, its a valid JSON which you can use in JavaScript:
这不是String，它是一个有效的 JSON，您可以在 JavaScript 中使用它：
var jsonData = [{"ZoneId": "1", "0": "1", "ZoneX": "29", "1": "29", "ZoneY": "27", "2": "27", "ZoneWidth": "76", "3": "76", "ZoneHeight": "61", "4": "61", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"},
{"ZoneId": "2", "0": "2", "ZoneX": "382", "1": "382", "ZoneY": "226", "2": "226", "ZoneWidth": "-117", "3": "-117", "ZoneHeight": "98", "4": "98", "ZoneImage": "46", "5": "46", "ZonePointTo": "3", "6": "3"},
{"ZoneId": "3", "0": "3", "ZoneX": "108", "1": "108", "ZoneY": "74", "2": "74", "ZoneWidth": "363", "3": "363", "ZoneHeight": "83", "4": "83", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"}];
for(index in jsonData) {
alert(JSON.stringify(jsonData[index]));
}
回答by Oli Soproni B.
If your having a return like this
如果你有这样的回报
var json_string = "[{"0":"1","1":"29","2":"27","3":"76","4":"61","5":"46","6":"2","ZoneId":"1","ZoneX":"29","ZoneY":"27","ZoneWidth":"76","ZoneHeight":"61","ZoneImage":"46","ZonePointTo":"2"},{"0":"2","1":"382","2":"226","3":"-117","4":"98","5":"46","6":"3","ZoneId":"2","ZoneX":"382","ZoneY":"226","ZoneWidth":"-117","ZoneHeight":"98","ZoneImage":"46","ZonePointTo":"3"},{"0":"3","1":"108","2":"74","3":"363","4":"83","5":"46","6":"2","ZoneId":"3","ZoneX":"108","ZoneY":"74","ZoneWidth":"363","ZoneHeight":"83","ZoneImage":"46","ZonePointTo":"2"}]"
then you can use the JSON.parse() function
那么你可以使用 JSON.parse() 函数
and it will decode the stringify json data
它将解码 stringify json 数据
and it will return you
它会回报你
[{"ZoneId": "1", "0": "1", "ZoneX": "29", "1": "29", "ZoneY": "27", "2": "27", "ZoneWidth": "76", "3": "76", "ZoneHeight": "61", "4": "61", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"},
{"ZoneId": "2", "0": "2", "ZoneX": "382", "1": "382", "ZoneY": "226", "2": "226", "ZoneWidth": "-117", "3": "-117", "ZoneHeight": "98", "4": "98", "ZoneImage": "46", "5": "46", "ZonePointTo": "3", "6": "3"},
{"ZoneId": "3", "0": "3", "ZoneX": "108", "1": "108", "ZoneY": "74", "2": "74", "ZoneWidth": "363", "3": "363", "ZoneHeight": "83", "4": "83", "ZoneImage": "46", "5": "46", "ZonePointTo": "2", "6": "2"}]
since the return is already a json object then no need to use JSON.parse();
由于返回已经是一个 json 对象，所以不需要使用 JSON.parse();
