Javascript - 找到参数下面所有 3 或 5 的倍数的总和

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/47076052/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-29 07:10:45  来源:igfitidea点击:

Javascript - Find the sum of all the multiples of 3 or 5 below parameter

javascript

提问by Wireless Squad

I'm attempting to do what the title says however this code does not function. Can anyone give any tips on how to make this return correctly?

我正在尝试按照标题所说的做,但是此代码不起作用。任何人都可以提供有关如何正确返回的任何提示吗?

function multiples(number) {
  let sum = 0;
  for (let i = 0; i <= number; i++) {

  if (i % 3 === 0 || i % 5 === 0) {
    sum += i;
      }
    }
  }

回答by gurvinder372

You are just missing a returnstatement.

你只是缺少一个return声明。

Demo

演示

function multiples(number) {
  let sum = 0;
  for (let i = 0; i <= number; i++) {

    if (i % 3 === 0 || i % 5 === 0) {
      sum += i;
    }
  }
  return sum;
}

console.log( multiples(10) );
console.log( multiples(5) );
console.log( multiples(6) );

回答by Sunny Patel

<script type="text/javascript">
var sum = 0;
var number = 15;
for (var i = 0; i <= number; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
        alert(i);
        sum += i;
    }
}

alert(sum); // 60
</script>

回答by stesel

const multiplies = (number) => {
    return Array.apply(null, {length: number}).map((v, i) => i).reduce((sum, i) => {
        return (i % 3 === 0 || i % 5 === 0) ? sum + i : sum;
    }, 0);
}