Android相机意图

Android camera intent

提问by Alexander Oleynikov

I need to push an intent to default camera application to make it take a photo, save it and return an URI. Is there any way to do this?

我需要将意图推送到默认相机应用程序，以使其拍照、保存并返回 URI。有没有办法做到这一点？

回答by Alexander Oleynikov

private static final int TAKE_PICTURE = 1;    
private Uri imageUri;

public void takePhoto(View view) {
    Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    File photo = new File(Environment.getExternalStorageDirectory(),  "Pic.jpg");
    intent.putExtra(MediaStore.EXTRA_OUTPUT,
            Uri.fromFile(photo));
    imageUri = Uri.fromFile(photo);
    startActivityForResult(intent, TAKE_PICTURE);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    switch (requestCode) {
    case TAKE_PICTURE:
        if (resultCode == Activity.RESULT_OK) {
            Uri selectedImage = imageUri;
            getContentResolver().notifyChange(selectedImage, null);
            ImageView imageView = (ImageView) findViewById(R.id.ImageView);
            ContentResolver cr = getContentResolver();
            Bitmap bitmap;
            try {
                 bitmap = android.provider.MediaStore.Images.Media
                 .getBitmap(cr, selectedImage);

                imageView.setImageBitmap(bitmap);
                Toast.makeText(this, selectedImage.toString(),
                        Toast.LENGTH_LONG).show();
            } catch (Exception e) {
                Toast.makeText(this, "Failed to load", Toast.LENGTH_SHORT)
                        .show();
                Log.e("Camera", e.toString());
            }
        }
    }
}

回答by Ryan

Try the following I found here

尝试以下我在这里找到的

Intent intent = new Intent("android.media.action.IMAGE_CAPTURE");
startActivityForResult(intent, 0);

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
  if (resultCode == Activity.RESULT_OK && requestCode == 0) {
    String result = data.toURI();
    // ...
  }
}

回答by Albert Vila Calvo

It took me some hours to get this working. The code it's almost a copy-paste from developer.android.com, with a minor difference.

我花了几个小时才开始工作。代码几乎是从developer.android.com复制粘贴的，有细微差别。

Request this permission on the AndroidManifest.xml:

在 上请求此权限AndroidManifest.xml：

<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

On your Activity, start by defining this:

在您的 上Activity，首先定义以下内容：

static final int REQUEST_IMAGE_CAPTURE = 1;
private Bitmap mImageBitmap;
private String mCurrentPhotoPath;
private ImageView mImageView;

Then fire this Intentin an onClick:

然后Intent在一个onClick：

Intent cameraIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
if (cameraIntent.resolveActivity(getPackageManager()) != null) {
    // Create the File where the photo should go
    File photoFile = null;
    try {
        photoFile = createImageFile();
    } catch (IOException ex) {
        // Error occurred while creating the File
        Log.i(TAG, "IOException");
    }
    // Continue only if the File was successfully created
    if (photoFile != null) {
        cameraIntent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(photoFile));
        startActivityForResult(cameraIntent, REQUEST_IMAGE_CAPTURE);
    }
}

Add the following support method:

添加以下支持方法：

private File createImageFile() throws IOException {
    // Create an image file name
    String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
    String imageFileName = "JPEG_" + timeStamp + "_";
    File storageDir = Environment.getExternalStoragePublicDirectory(
            Environment.DIRECTORY_PICTURES);
    File image = File.createTempFile(
            imageFileName,  // prefix
            ".jpg",         // suffix
            storageDir      // directory
    );

    // Save a file: path for use with ACTION_VIEW intents
    mCurrentPhotoPath = "file:" + image.getAbsolutePath();
    return image;
}

Then receive the result:

然后得到结果：

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == REQUEST_IMAGE_CAPTURE && resultCode == RESULT_OK) {
        try {
            mImageBitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath));
            mImageView.setImageBitmap(mImageBitmap);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

What made it work is the MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath)), which is different from the code from developer.android.com. The original code gave me a FileNotFoundException.

使它起作用的是MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath))，它与developer.android.com的代码不同。原始代码给了我一个FileNotFoundException.

回答by mohit rathore

Try the following I found Here's a link

尝试以下我发现这是一个链接

If your app targets M and above and declares as using the CAMERA permission which is not granted, then attempting to use this action will result in a SecurityException.

如果您的应用以 M 及以上为目标并声明使用未授予的 CAMERA 权限，则尝试使用此操作将导致 SecurityException。

EasyImage.openCamera(Activity activity, int type);

EasyImage.openCamera(Activity activity, int type);

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    EasyImage.handleActivityResult(requestCode, resultCode, data, this, new DefaultCallback() {
        @Override
        public void onImagePickerError(Exception e, EasyImage.ImageSource source, int type) {
            //Some error handling
        }

        @Override
        public void onImagesPicked(List<File> imagesFiles, EasyImage.ImageSource source, int type) {
            //Handle the images
            onPhotosReturned(imagesFiles);
        }
    });
}

回答by Aishik kirtaniya

I found a pretty simple way to do this. Use a button to open it using an on clicklistener to start the function openc(), like this:

我找到了一个非常简单的方法来做到这一点。使用按钮打开它，使用on click侦听器启动函数openc()，如下所示：

String fileloc;
private void openc()
{
    Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    File f = null;
    try 
    {
        f = File.createTempFile("temppic",".jpg",getApplicationContext().getCacheDir());
        if (takePictureIntent.resolveActivity(getPackageManager()) != null)
        {               
            takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT,FileProvider.getUriForFile(profile.this, BuildConfig.APPLICATION_ID+".provider",f));
            fileloc = Uri.fromFile(f)+"";
            Log.d("texts", "openc: "+fileloc);
            startActivityForResult(takePictureIntent, 3);
        }
    } 
    catch (IOException e) 
    {
        e.printStackTrace();
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
{
    super.onActivityResult(requestCode, resultCode, data);
    if(requestCode == 3 && resultCode == RESULT_OK) {
        Log.d("texts", "onActivityResult: "+fileloc);
        // fileloc is the uri of the file so do whatever with it
    }
}

You can do whatever you want with the urilocation string. For instance, I send it to an image cropper to crop the image.

您可以对uri位置字符串执行任何操作。例如，我将它发送到图像裁剪器来裁剪图像。

回答by anupam sharma

try this code

试试这个代码

Intent photo= new Intent("android.media.action.IMAGE_CAPTURE");
                    startActivityForResult(photo, CAMERA_PIC_REQUEST);