如何在 C++ 中初始化一个字符串集？
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How to initialize a string set in C++?
提问by Crocode
I have a few words to be initialized while declaring a string set.
在声明字符串集时，我有几个词要初始化。
...
using namespace std;
set<string> str;
/*str has to contain some names like "John", "Kelly", "Amanda", "Kim".*/
I don't want to use str.insert("Name");each time.
我不想str.insert("Name");每次都用。
Any help would be appreciated.
任何帮助，将不胜感激。
回答by orlp
Using C++11:
使用 C++11：
std::set<std::string> str = {"John", "Kelly", "Amanda", "Kim"};
Otherwise:
除此以外：
std::string tmp[] = {"John", "Kelly", "Amanda", "Kim"};
std::set<std::string> str(tmp, tmp + sizeof(tmp) / sizeof(tmp[0]));
回答by Drew Dormann
In C++11
在 C++11 中
Use initializer lists.
使用初始化列表。
set<string> str { "John", "Kelly", "Amanda", "Kim" };
In C++03(I'm voting up @john's answer. It's very close what I would have given.)
在 C++03 中（我投票支持@john 的答案。它非常接近我给出的答案。）
Use the std::set( InputIterator first, InputIterator last, ...)constructor.
使用std::set( InputIterator first, InputIterator last, ...)构造函数。
string init[] = { "John", "Kelly", "Amanda", "Kim" };
set<string> str(init, init + sizeof(init)/sizeof(init[0]) );
回答by john
There's lots of ways you can do this, here's one
有很多方法可以做到这一点，这是一种
string init[] = { "John", "Kelly", "Amanda", "Kim" };
set<string> str(init, init + 4);
回答by CyberGuy
if you are not c++0x:
如果你不是 c++0x：
You should look at boost::assign
你应该看看 boost::assign
http://www.boost.org/doc/libs/1_39_0/libs/assign/doc/index.html#list_of
http://www.boost.org/doc/libs/1_39_0/libs/assign/doc/index.html#list_of
Also take a look at:
另请看：
Using STL/Boost to initialize a hard-coded set<vector<int> >
使用 STL/Boost 初始化硬编码 set<vector<int> >
#include <boost/assign/list_of.hpp>
#include <vector>
#include <set>
using namespace std;
using namespace boost::assign;
int main()
{
set<int> A = list_of(1)(2)(3)(4);
return 0; // not checked if compile
}
回答by oldrinb
There's multiple ways to do this. Using C++11, you can try either...
有多种方法可以做到这一点。使用 C++11，你可以尝试...
std::set<std::string> set {
"John", "Kelly", "Amanda", "Kim"
};
... which uses an initializer list, or std::beginand std::end...
... 使用初始化列表，或std::begin和std::end...
std::string vals[] = { "John", "Kelly", "Amanda", "Kim" };
std::set<std::string> set(std::begin(vals), std::end(vals));
回答by Moshe Gottlieb
Create an array of strings(C array) and initialize the set with it's values (array pointers as iterators):std::string values[] = { "John", "Kelly", "Amanda", "Kim" };
std::set s(values,values + sizeof(values)/sizeof(std::string));
创建一个字符串数组（C 数组）并用它的值（数组指针作为迭代器）初始化该集合：std::string values[] = { "John", "Kelly", "Amanda", "Kim" };
std::set s(values,values + sizeof(values)/sizeof(std::string));
回答by Hakeem
the easiest way
最简单的方法
#define str string
....
set<str> so;
so.insert("John");
so.insert("Kelly");
so.insert("Amanda");
so.insert("Kim");
