C++ 异常 - 抛出一个字符串
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C++ Exception - Throw a String
提问by Jimmy
I'm having a small issue with my code. For some reason , when i try to throw a string with the code below ,i get an error in visual studio.
我的代码有一个小问题。出于某种原因，当我尝试使用下面的代码抛出一个字符串时，我在 Visual Studio 中收到错误消息。
#include <string>
#include <iostream>
using namespace std;
int main()
{
char input;
cout << "\n\nWould you like to input? (y/n): ";
cin >> input;
input = tolower(input);
try
{
if (input != 'y')
{
throw ("exception ! error");
}
}
catch (string e)
{
cout << e << endl;
}
}
Error :
错误 ：
回答by Mr.C64
Throwing a string is really a bad idea.
扔一根绳子真的是个坏主意。
Feel free to define a custom exception class, and have a string embedded inside (or just derive your custom exception class from std::runtime_error, pass an error message to the constructor, and use the what()method to get the error string at the catch-site), but do notthrow a string!
随意定义一个自定义异常类，并在其中嵌入一个字符串（或者只是从 派生自定义异常类std::runtime_error，将错误消息传递给构造函数，并使用该what()方法在捕获站点获取错误字符串），但是千万不能丢一个字符串！
回答by Syntactic Fructose
you are currently throwing a const char*and not a std::string, instead you should be throwing string("error")
您当前正在抛出 aconst char*而不是 a std::string，而是应该抛出string("error")
edit: the error is resolved with
编辑：错误已解决
throw string("exception ! error");
