PHP 获取数组的最后 3 个元素
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PHP get the last 3 elements of an array
提问by alex
I have an array:
我有一个数组：
[13] => Array
(
[0] => joe
[1] => 0
[14] => Array
(
[0] => bob
[1] => 0
)
[15] => Array
(
[0] => sue
[1] => 0
)
[16] => Array
(
[0] => john
[1] => 0
)
[17] => Array
(
[0] => harry
[1] => 0
)
[18] => Array
(
[0] => larry
[1] => 0
)
How can I get the last 3 elements while preserving the keys? (the number of elements in the array may vary, so I cannot simply slice after the 2nd element)
如何在保留键的同时获取最后 3 个元素？（数组中的元素数量可能会有所不同，所以我不能简单地在第二个元素之后切片）
So the output would be:
所以输出将是：
[16] => Array
(
[0] => john
[1] => 0
)
[17] => Array
(
[0] => harry
[1] => 0
)
[18] => Array
(
[0] => larry
[1] => 0
)
回答by Andreas Wong
If you want to preserve key, you can pass in true as the fourth argument:
如果要保留密钥，可以传入 true 作为第四个参数：
array_slice($a, -3, 3, true);
回答by fabrik
回答by codaddict
You can use array_slicewith offset as -3so you don't have to worry about the array length also by setting preserve_keysparameter to TRUE.
您可以array_slice与 offset 一起使用，-3这样您也不必担心数组长度也可以通过将preserve_keys参数设置为TRUE.
$arr = array_slice($arr,-3,3,true);
回答by Silver Light
You can use array_slice():
您可以使用array_slice()：
<?php
// -3 = start from the end
// true = preserve_keys
$result = array_slice($array, 0, -3, true);
?>
