Java 在 Android 上将字符串转换为整数
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Converting a string to an integer on Android
提问by James Rattray
How do I convert a string into an integer?
如何将字符串转换为整数？
I have a textbox I have the user enter a number into:
我有一个文本框，我让用户在其中输入一个数字：
EditText et = (EditText) findViewById(R.id.entry1);
String hello = et.getText().toString();
And the value is assigned to the string hello.
并将该值分配给 string hello。
I want to convert it to a integer so I can get the number they typed; it will be used later on in code.
我想把它转换成一个整数，这样我就可以得到他们输入的数字；稍后将在代码中使用它。
Is there a way to get the EditTextto a integer? That would skip the middle man. If not, string to integer will be just fine.
有没有办法得到EditText一个整数？那将跳过中间人。如果没有，字符串到整数就可以了。
采纳答案by Jon
See the Integer class and the static parseInt()method:
查看 Integer 类和静态parseInt()方法：
http://developer.android.com/reference/java/lang/Integer.html
http://developer.android.com/reference/java/lang/Integer.html
Integer.parseInt(et.getText().toString());
You will need to catch NumberFormatExceptionthough in case of problems whilst parsing, so:
如果NumberFormatException在解析时出现问题，您将需要捕获，因此：
int myNum = 0;
try {
myNum = Integer.parseInt(et.getText().toString());
} catch(NumberFormatException nfe) {
System.out.println("Could not parse " + nfe);
}
回答by manuel
int in = Integer.valueOf(et.getText().toString());
//or
int in2 = new Integer(et.getText().toString());
回答by Tren Narek
You should covert String to float. It is working.
您应该将 String 转换为浮动。这是工作。
float result = 0;
if (TextUtils.isEmpty(et.getText().toString()) {
return;
}
result = Float.parseFloat(et.getText().toString());
tv.setText(result);
回答by Ravi
Best way to convert your string into int is :
将字符串转换为 int 的最佳方法是：
EditText et = (EditText) findViewById(R.id.entry1);
String hello = et.getText().toString();
int converted=Integer.parseInt(hello);
回答by Ashish Sahu
Use regular expression:
使用正则表达式：
int i=Integer.parseInt("hello123".replaceAll("[\D]",""));
int j=Integer.parseInt("123hello".replaceAll("[\D]",""));
int k=Integer.parseInt("1h2el3lo".replaceAll("[\D]",""));
output:
输出：
i=123;
j=123;
k=123;
回答by Ashish Sahu
Use regular expression:
使用正则表达式：
String s="your1string2contain3with4number";
int i=Integer.parseInt(s.replaceAll("[\D]", ""));
output: i=1234;
输出：i=1234；
If you need first number combination then you should try below code:
如果您需要第一个数字组合，那么您应该尝试以下代码：
String s="abc123xyz456";
int i=NumberFormat.getInstance().parse(s).intValue();
output: i=123;
输出：i=123；
回答by Abdul Rizwan
You can use the following to parse a string to an integer:
您可以使用以下内容将字符串解析为整数：
int value=Integer.parseInt(textView.getText().toString());
int value=Integer.parseInt(textView.getText().toString());
(1)input:12 then it will work.. because textview has taken this 12 number as "12" string.
(1) input:12 那么它会起作用..因为textview已经将这个12数字作为“12”字符串。
(2) input:"abdul" then it will throw an exception that is NumberFormatException. So to solve this we need to use try catch as I have mention below:
(2) input:"abdul" 那么它会抛出一个异常，即 NumberFormatException。所以为了解决这个问题，我们需要使用 try catch ，正如我在下面提到的：
int tax_amount=20;
EditText edit=(EditText)findViewById(R.id.editText1);
try
{
int value=Integer.parseInt(edit.getText().toString());
value=value+tax_amount;
edit.setText(String.valueOf(value));// to convert integer to string
}catch(NumberFormatException ee){
Log.e(ee.toString());
}
You may also want to refer to the following link for more information: http://developer.android.com/reference/java/lang/Integer.html
您可能还想参考以下链接了解更多信息：http: //developer.android.com/reference/java/lang/Integer.html
回答by Brett Moan
You can also do it one line:
你也可以用一行来做：
int hello = Integer.parseInt(((Button)findViewById(R.id.button1)).getText().toString().replaceAll("[\D]", ""));
Reading from order of execution
从执行顺序读取
- grab the view using
findViewById(R.id.button1) - use
((Button)______)to cast theViewas aButton - Call
.GetText()to get the text entry from Button - Call
.toString()to convert the Character Varying to a String - Call
.ReplaceAll()with"[\\D]"to replace all Non Digit Characters with "" (nothing) - Call
Integer.parseInt()grab and return an integer out of the Digit-only string.
- 使用获取视图
findViewById(R.id.button1) - 用于
((Button)______)将其转换View为Button - 调用
.GetText()以从 Button 获取文本条目 - 调用
.toString()以将 Character Varying 转换为 String - 调用
.ReplaceAll()with"[\\D]"将所有非数字字符替换为“”（无） - 调用
Integer.parseInt()grab 并从仅数字字符串中返回一个整数。
回答by Ravi Makvana
Try this code it's really working.
试试这个代码它真的有效。
int number = 0;
try {
number = Integer.parseInt(YourEditTextName.getText().toString());
} catch(NumberFormatException e) {
System.out.println("parse value is not valid : " + e);
}
回答by Ravi Makvana
Use regular expression is best way to doing this as already mentioned by ashish sahu
正如ashish sahu 已经提到的那样，使用正则表达式是最好的方法
public int getInt(String s){
return Integer.parseInt(s.replaceAll("[\D]", ""));
}
