C++ 如何使用宏参数作为字符串文字？
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How to use Macro argument as string literal?
提问by Ian
I am trying to figure out how to write a macro that will pass both a string literal representation of a variable name along with the variable itself into a function.
我想弄清楚如何编写一个宏，将变量名的字符串文字表示和变量本身传递给函数。
For example given the following function.
例如给出以下函数。
void do_something(string name, int val)
{
cout << name << ": " << val << endl;
}
I would want to write a macro so I can do this:
我想写一个宏，这样我就可以做到这一点：
int my_val = 5;
CALL_DO_SOMETHING(my_val);
Which would print out: my_val: 5
哪个会打印出来： my_val: 5
I tried doing the following:
我尝试执行以下操作：
#define CALL_DO_SOMETHING(VAR) do_something("VAR", VAR);
However, as you might guess, the VAR inside the quotes doesn't get replaced, but is just passed as the string literal "VAR". So I would like to know if there is a way to have the macro argument get turned into a string literal itself.
但是，正如您可能猜到的，引号内的 VAR 不会被替换，而只是作为字符串文字“VAR”传递。所以我想知道是否有办法让宏参数本身变成字符串文字。
回答by Morwenn
回答by chris
You want to use the stringizing operator:
您想使用字符串化运算符：
#define STRING(s) #s
int main()
{
const char * cstr = STRING(abc); //cstr == "abc"
}
回答by Mikele Shtembari
#define NAME(x) printf("Hello " #x);
main(){
NAME(Ian)
}
//will print: Hello Ian
回答by Zili
Perhaps you try this solution:
也许你试试这个解决方案：
#define QUANTIDISCHI 6
#define QUDI(x) #x
#define QUdi(x) QUDI(x)
. . .
. . .
unsigned char TheNumber[] = "QUANTIDISCHI = " QUdi(QUANTIDISCHI) "\n";
