Java 打开图片
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Opening an image
提问by wokparty
I am an idiot. Why can't I read any files?
我是一个白痴。为什么我无法读取任何文件？
import java.awt.Image;
import java.io.File;
import java.io.IOException;
import javax.imageio.ImageIO;
public class mainClass {
public static void main(String[] args) {
try {
Image picture = ImageIO.read(new File("picture.png"));
} catch (IOException e) {
e.printStackTrace();
}
}
}
And the file is in the src folder for sure.
并且该文件肯定在 src 文件夹中。
But it throws the exception everytime even though the file is there, no misspellings.
但是即使文件在那里，它每次也会抛出异常，没有拼写错误。
edit: The first sentence was true, I didn't put the image in the root.
编辑：第一句话是对的，我没有把图像放在根目录中。
回答by Jasonw
Been there as well, know that feeling. Anyway, try print out current working directory and that will tell you exactlywhere is the application really read from.
也去过那里，知道那种感觉。无论如何，尝试打印出当前工作目录，这将告诉你究竟哪里是真正的应用程序读取。
try
{
Image picture = ImageIO.read(new File("picture.png"));
}
catch (IOException e)
{
String workingDir = System.getProperty("user.dir");
System.out.println("Current working directory : " + workingDir);
e.printStackTrace();
}
回答by Thiago Souza
Try to specify the path of your image. For example:
尝试指定图像的路径。例如：
Image picture = ImageIO.read(new File("C:/Desktop/picture.png"));
Or if the image is in your workspace, for example:
或者，如果图像在您的工作区中，例如：
Image picture = ImageIO.read(new File("C:/workspace/Project/src/picture.png"));
You can see the image location (the path of your image) clicking with the right button of the mouse in the image, then Properties.
您可以看到图像位置（图像的路径）在图像中单击鼠标右键，然后单击属性。
You can use one slah ( / ) or two backslashs ( \\ ) to separate the directories of the path.
您可以使用一个斜杠 ( / ) 或两个反斜杠 ( \\ ) 来分隔路径的目录。
回答by Joop Eggen
There is a dichotomy in java.
java中有一个二分法。
If your file is part of the deliverable project, a file which can be packed in the application jar file, then it is a resource.
Image picture = ImageIO.read(SomeClassOfYours.class.getResource("/picture.png"));
如果你的文件是可交付项目的一部分，一个可以打包在应用程序jar文件中的文件，那么它就是一个资源。
Image picture = ImageIO.read(SomeClassOfYours.class.getResource("/picture.png"));
The path is relative to that class, and can be made an absolute path. All on the java class path of the application.
该路径是相对于该类的，可以设为绝对路径。全部在应用程序的 java 类路径上。
If your file is a file system file, a
File, then the path best is a full absolute path. A relative path depends at which working directory the application is run, and that might differ.Image picture = ImageIO.read(new File("C:/.../src/picture.png"));
如果您的文件是文件系统文件a
File，那么路径最好是完整的绝对路径。相对路径取决于运行应用程序的工作目录，这可能会有所不同。Image picture = ImageIO.read(new File("C:/.../src/picture.png"));
The question seems to indicate that the image is a read-only part of the application, in which case it is a resource file. The path mustbe case sensitive, and the path separator mustbe a forward slash /.
这个问题似乎表明图像是应用程序的只读部分，在这种情况下它是一个资源文件。路径必须区分大小写，路径分隔符必须是正斜杠/。
