C# 在 BitmapSource 和 Bitmap 之间转换有什么好方法吗?
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Is there a good way to convert between BitmapSource and Bitmap?
提问by JohannesH
As far as I can tell the only way to convert from BitmapSource to Bitmap is through unsafe code... Like this (from Lesters WPF blog):
据我所知,从 BitmapSource 转换为 Bitmap 的唯一方法是通过不安全的代码......像这样(来自Lesters WPF 博客):
myBitmapSource.CopyPixels(bits, stride, 0);
unsafe
{
  fixed (byte* pBits = bits)
  {
      IntPtr ptr = new IntPtr(pBits);
      System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap(
        width,
        height,
        stride,
        System.Drawing.Imaging.PixelFormat.Format32bppPArgb,ptr);
      return bitmap;
  }
}
To do the reverse:
反过来做:
System.Windows.Media.Imaging.BitmapSource bitmapSource =
  System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap(
    bitmap.GetHbitmap(),
    IntPtr.Zero,
    Int32Rect.Empty,
    System.Windows.Media.Imaging.BitmapSizeOptions.FromEmptyOptions());
Is there an easier way in the framework? And what is the reason it isn't in there (if it's not)? I would think it's fairly usable.
框架中有更简单的方法吗?它不在那里的原因是什么(如果不是)?我觉得还是蛮好用的。
The reason I need it is because I use AForge to do certain image operations in an WPF app. WPF wants to show BitmapSource/ImageSource but AForge works on Bitmaps.
我需要它的原因是因为我使用 AForge 在 WPF 应用程序中执行某些图像操作。WPF 想要显示 BitmapSource/ImageSource,但 AForge 可以处理位图。
采纳答案by josef.axa
It is possible to do without using unsafe code by using Bitmap.LockBitsand copy the pixels from the BitmapSourcestraight to the Bitmap
通过使用Bitmap.LockBits和复制像素从BitmapSource直线到Bitmap
Bitmap GetBitmap(BitmapSource source) {
  Bitmap bmp = new Bitmap(
    source.PixelWidth,
    source.PixelHeight,
    PixelFormat.Format32bppPArgb);
  BitmapData data = bmp.LockBits(
    new Rectangle(Point.Empty, bmp.Size),
    ImageLockMode.WriteOnly,
    PixelFormat.Format32bppPArgb);
  source.CopyPixels(
    Int32Rect.Empty,
    data.Scan0,
    data.Height * data.Stride,
    data.Stride);
  bmp.UnlockBits(data);
  return bmp;
}
回答by caesay
Is this what your looking for?
这是您要找的吗?
Bitmap bmp = System.Drawing.Image.FromHbitmap(pBits);
回答by melvas
You can just use these two methods:
你可以只使用这两种方法:
public static BitmapSource ConvertBitmap(Bitmap source)
{
    return System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap(
                  source.GetHbitmap(),
                  IntPtr.Zero,
                  Int32Rect.Empty,
                  BitmapSizeOptions.FromEmptyOptions());
}
public static Bitmap BitmapFromSource(BitmapSource bitmapsource)
{
    Bitmap bitmap;
    using (var outStream = new MemoryStream())
    {
        BitmapEncoder enc = new BmpBitmapEncoder();
        enc.Frames.Add(BitmapFrame.Create(bitmapsource));
        enc.Save(outStream);
        bitmap = new Bitmap(outStream);
    }
    return bitmap;
}
It works perfectly for me.
它非常适合我。
回答by user3318309
Here a code to set transparent background to any bitmap resource within a Resource Dictionary (not Resources.resx often used in Windows.Forms age). I call this methode before InitializeComponent() - methode. The methodes 'ConvertBitmap(Bitmap source)' and BitmapFromSource(BitmapSource bitmapsource) are mentioned in post from melvas above.
这里是为资源字典中的任何位图资源设置透明背景的代码(不是在 Windows.Forms 时代经常使用的 Resources.resx)。我在 InitializeComponent() - methode 之前调用此方法。上面 melvas 的帖子中提到了方法 'ConvertBitmap(Bitmap source)' 和 BitmapFromSource(BitmapSource bitmapsource)。
private void SetBitmapResourcesTransparent()
    {
        Image img;
        BitmapSource bmpSource;
        System.Drawing.Bitmap bmp;
        foreach (ResourceDictionary resdict in Application.Current.Resources.MergedDictionaries)
        {
            foreach (DictionaryEntry dictEntry in resdict)
            {
                // search for bitmap resource
                if ((img = dictEntry.Value as Image) is Image 
                    && (bmpSource = img.Source as BitmapSource) is BitmapSource
                    && (bmp = BitmapFromSource(bmpSource)) != null)
                {
                    // make bitmap transparent and assign it back to ressource
                    bmp.MakeTransparent(System.Drawing.Color.Magenta);
                    bmpSource = ConvertBitmap(bmp);
                    img.Source = bmpSource;
                }
            }
        }
    }
回答by Mauro Sampietro
This is neat and faster than light:
这比光还快:
  return Imaging.CreateBitmapSourceFromHBitmap( bitmap.GetHbitmap(), IntPtr.Zero,
      Int32Rect.Empty, BitmapSizeOptions.FromEmptyOptions() );
回答by Andreas
You can share the pixeldata between both namespaces. You don't have to convert.
您可以在两个命名空间之间共享像素数据。你不必转换。
Use the SharedBitmapSource. https://stackoverflow.com/a/32841840/690656
使用 SharedBitmapSource。https://stackoverflow.com/a/32841840/690656

