Laravel 验证：仅当存在另一个字段时才验证字段
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Laravel validation: validate field only if another is present
提问by dani24
I wanted to validate an 'account_id' only if 'needs_login' is present. I did this:
我想仅在存在“needs_login”时验证“account_id”。我这样做了：
$rules = [
'account_id' => ['required_with:needs_login','custom_validation']
];
But it doesn't work, because if needs_login field is not present but account_id has some value, then it tries to do the 'custom_validation'. I also tried to put the 'sometimes' parameter
但它不起作用，因为如果 Needs_login 字段不存在但 account_id 有一些值，那么它会尝试执行“custom_validation”。我也试图把“有时”参数
$rules = [
'account_id' => ['required_with:needs_login', 'sometimes', 'custom_validation']
];
but it didn't work.
但它没有用。
Any ideas?
有任何想法吗？
P.S.:Remember that I wanted to validate the account_id only if needs_login is present, not to check if account_id is present if needs_login does.
PS：请记住，我只想在需要登录时验证 account_id，而不是在需要登录时检查 account_id 是否存在。
采纳答案by DonnaJo
Something like this works for Laravel 5 if you are going the 'sometimes' route. Perhaps you can adapt for L4? Looks like it's the same in the Docs.
如果您要走“有时”路线，这样的事情适用于 Laravel 5。也许你可以适应L4？看起来它在 Docs 中是一样的。
$validation = Validator::make($formData, [
'some_form_item' => 'rule_1|rule_2'
]
$validation->sometimes('account_id', 'required', function($input){
return $input->needs_login == true;
});
回答by IllegalPigeon
Have you tried required_if?
你试过required_if吗？
$rules = [
'account_id' => ['required_if:needs_login,1']
];
