xcode 在模拟器上检测 iPhone 6/Plus 时遇到问题
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Having issue with detect iPhone 6/Plus on simulator
提问by Mc.Lover
I am trying to build a version of my app specifically for iPhone 6 and 6 Plus , whereas I don't have any hardware , I have to test on the simulator ! but it seems , simulator has a strange bug ! first and for most I get screen resolutions and scales , by this code :
我正在尝试专门为 iPhone 6 和 6 Plus 构建我的应用程序版本，而我没有任何硬件，我必须在模拟器上进行测试！但似乎，模拟器有一个奇怪的错误！首先，对于大多数人来说，我通过以下代码获得屏幕分辨率和比例：
UIScreen *mainScreen = [UIScreen mainScreen];
NSLog(@"Screen bounds: %@, Screen resolution: %@, scale: %f, nativeScale: %f",
NSStringFromCGRect(mainScreen.bounds), mainScreen.coordinateSpace, mainScreen.scale, mainScreen.nativeScale);
so here is how detect iPhone 6 and 6Plus (Portrait mode):
所以这里是如何检测 iPhone 6 和 6Plus（纵向模式）：
#define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && [UIScreen mainScreen].bounds.size.height == 667)
#define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && [UIScreen mainScreen].bounds.size.height == 736)
the problem is ! when I lunch my app on iPhone6/Plus simulator , compiler gives me the sceen information of iPhone 4" display :
问题是 ！当我在 iPhone6/Plus 模拟器上吃午饭时，编译器给了我 iPhone 4" 显示器的屏幕信息：
2014-09-28 12:32:08.153 WOD[2924:42290]
Screen bounds: {{0, 0}, {320, 568}}, Screen resolution: <UIScreen: 0x7fa15be0f9b0; bounds = {{0, 0}, {320, 568}}; mode = <UIScreenMode: 0x7fa15bd0d4a0;
size = 640.000000 x 1136.000000>>, scale: 2.000000, nativeScale: 2.000000
But it works fine on new project ! (I cannot create a new project and start over again !).
I cleaned code, delete build folder, change project's name,and reset Simulator contents settingbut still gives me the information of 4" display ! .
但它在新项目上运行良好！（我无法创建新项目并重新开始！）。I cleaned code, delete build folder, change project's name, 和 resetSimulator contents setting但仍然给我 4" 显示器的信息！.
I have checked this Q/Abut answers require a real device !
我已经检查了这个Q/A但答案需要一个真实的设备！
回答by Mc.Lover
The main reason I faced with this problem was I build my application with Xcode 5and open it with Xcode 6
我面临这个问题的主要原因是我构建我的应用程序Xcode 5并打开它Xcode 6
Solution :
解决方案 ：
Add Launch Image for Retina HD 5.5 and 4.7 :
为 Retina HD 5.5 和 4.7 添加启动图像：
Now you can detect iPhone 6/Plus on simulator without having a real device :
现在您可以在模拟器上检测 iPhone 6/Plus，而无需真正的设备：
#define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 667)
#define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 736)
回答by yoshitech
Just in case you need to detect iPhone 6/6Plus in landscape, use this.
万一您需要在横向检测 iPhone 6/6Plus，请使用它。
#define iPhone6 ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 667)
#define iPhone6Plus ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone && MAX([UIScreen mainScreen].bounds.size.height,[UIScreen mainScreen].bounds.size.width) == 736)
