在 Laravel 中找到?例子

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时间:2020-09-14 13:17:31  来源:igfitidea点击:

find in set in laravel ? example

phpmysqllaravellaravel-5.1

提问by Ravi Kadia

I am new in laravel. My query is i need to find out value from comma separated field.

我是laravel的新手。我的查询是我需要从逗号分隔的字段中找出值。

Here is my table:

这是我的表:

tags_value

标签值

╔════╦══════════════╗
║ id ║     tags     ║
╠════╬══════════════╣
║  1 ║ css,html,php ║
║  2 ║ php,java,css ║
║  3 ║ java,c++,ios ║
╚════╩══════════════╝

This is my SQL query:

这是我的 SQL 查询:

$query = DB::table('tags_value')
         ->whereRaw(FIND_IN_SET('css', Tags))
         ->get();

but it's not working.

但它不起作用。

Please help me to solve this problem. Thanks in advance.

请帮我解决这个问题。提前致谢。

回答by Tim Biegeleisen

You need to escape the call to FIND_IN_SET()using quotes:

您需要将调用转义为FIND_IN_SET()使用引号:

$query = DB::table('tags_value')
         ->whereRaw('FIND_IN_SET(css,Tags)')
         ->get();

If you want to parameterize the column for which you search in FIND_IN_SET, then you can try something like this:

如果你想参数化你搜索的列FIND_IN_SET,那么你可以尝试这样的事情:

$colname = 'css'
$query = DB::table('tags_value')
         ->whereRaw('FIND_IN_SET(?,Tags)', [$colname])
         ->get();

回答by Mr. Engineer

Try this :

尝试这个 :

->whereRaw("FIND_IN_SET('css',tags)")