vb.net “maintainScrollPositionOnPostBack="true“" 不适用于谷歌浏览器
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“maintainScrollPositionOnPostBack=”true“ ” does not work with google chrome
提问by Pranav Kumar
Web.config Level => pages maintainScrollPositionOnPostBack="true" />
Page Level => <%@ Page MaintainScrollPositionOnPostback="true" %>
Code Level => Page.MaintainScrollPositionOnPostBack = true;
Browser Level => browser id="Chrome" parentID="Safari1Plus"> capabilities> capability name="supportsMaintainScrollPositionOnPostback" value="true" /> capabilities> browser>
Web.config Level => pages维持ScrollPositionOnPostBack="true" />
页面级别 => <%@ PageMaintainScrollPositionOnPostback="true" %>
代码级别 => Page.MaintainScrollPositionOnPostBack = true;
浏览器级别 => 浏览器 id="Chrome" parentID="Safari1Plus"> 能力> 能力名称="supportsMaintainScrollPositionOnPostback" value="true" /> 能力> 浏览器>
Any of the 4 waysmentioned above did not work with google chrome. It is working fine with firefox. Kindly provide any solution .
上面提到的 4 种方式中的任何一种都不适用于 google chrome。它在 Firefox 中运行良好。请提供任何解决方案。
回答by Darkseal
You can add this snippet to your ASP.NET Page/MasterPage (jQuery required):
您可以将此代码段添加到您的 ASP.NET 页面/MasterPage（需要 jQuery）：
<asp:HiddenField runat="server" ID="hfPosition" Value="" />
<script type="text/javascript">
$(function () {
var f = $("#<%=hfPosition.ClientID%>");
window.onload = function () {
var position = parseInt(f.val());
if (!isNaN(position)) {
$(window).scrollTop(position);
}
};
window.onscroll = function () {
var position = $(window).scrollTop();
f.val(position);
};
});
</script>
回答by ShaileshDev
I also faced same problem. I found one Javascript solution here.
我也面临同样的问题。我在这里找到了一个 Javascript 解决方案。
<script type = "text/javascript">
window.onload = function () {
var scrollY = parseInt('<%=Request.Form["scrollY"] %>');
if (!isNaN(scrollY)) {
window.scrollTo(0, scrollY);
}
};
window.onscroll = function () {
var scrollY = document.body.scrollTop;
if (scrollY == 0) {
if (window.pageYOffset) {
scrollY = window.pageYOffset;
}
else {
scrollY = (document.body.parentElement) ? document.body.parentElement.scrollTop : 0;
}
}
if (scrollY > 0) {
var input = document.getElementById("scrollY");
if (input == null) {
input = document.createElement("input");
input.setAttribute("type", "hidden");
input.setAttribute("id", "scrollY");
input.setAttribute("name", "scrollY");
document.forms[0].appendChild(input);
}
input.value = scrollY;
}
};
I hope this would help you.
我希望这会帮助你。
