XML Oracle:从多个重复的子节点中提取特定属性

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时间:2020-09-19 03:08:21  来源:igfitidea点击:

XML Oracle: Extract specific attribute from multiple repeating child nodes

sqlxmloracleplsql

提问by mrbTT

I'm having trouble understanding other questions I see, as they are a little bit different.

我无法理解我看到的其他问题,因为它们有点不同。

I'm getting a XML as response from a webservice vi UTL_HTTP. The XML has repeating child nodes and I want to extract only 1 specific value.

我从 web 服务 vi UTL_HTTP 得到一个 XML 作为响应。XML 具有重复的子节点,我只想提取 1 个特定值。

The response XML:

响应 XML:

<Customer>
    <Loyalty>
       <Client>
          <Identifications>
              <Identification>
                   <Form>Form1</Form>
                   <value>1234</value>
              </Identification>
              <Identification>
                   <Form>Form2</Form>
                   <value>4442</value>
              </Identification>
              <Identification>
                   <Form>Form3</Form>
                   <value>9995</value>
              </Identification>
           </Identifications>
       </Client>
    </Loyalty>
 </Customer>

I need to extract the the node <value>only where the node <Form>= "Form3".

我只需要<value>在节点<Form>=“Form3”的地方提取节点。

So, within my code, I receive the response from another function

所以,在我的代码中,我收到了另一个函数的响应

v_ds_xml_response XMLTYPE;
-- Here would lie the rest of the code (omitted) preparing the XML and next calling the function with    it:

V_DS_XML_RESPONSE := FUNCTION_CALL_WEBSERVICE(
      P_URL => V_DS_URL, --endpoint
      P_DS_XML => V_DS_XML, --the request XML
      P_ERROR => P_ERROR); 

With that, I created a LOOP to store the values. I've tried using WHERE and even creating a type (V_IDENTIFICATION below is the type), but It didn't return anything (null).

有了这个,我创建了一个 LOOP 来存储值。我试过使用 WHERE 甚至创建一个类型(下面的 V_IDENTIFICATION 是类型),但它没有返回任何内容(空)。

for r IN (
SELECT         
 ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="Form"]/text()') as form, 
     ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="value"]/text()') as value
   FROM   TABLE(XMLSequence(Extract(V_DS_XML_RESPONSE,'//*[local-name()="Customer"]'))) p

LOOP
V_IDENTIFICATION.FORM   := r.form;
V_IDENTIFICATION.VALUE  := r.value;
END LOOP;

SELECT 
       V_IDENTIFICATION.VALUE
INTO   
       P_LOYALTY_VALUE
FROM   dual
WHERE  V_IDENTIFICATION.TIPO = 'Form3';

Note, P_LOYALTY_VALUE is an OUT parameter from my Procedure

注意,P_LOYALTY_VALUE 是我的程序中的一个 OUT 参数

采纳答案by mrbTT

Aaand I managed to find the solution, which is quite simple, just added [text()="Form3"]/.../" to predicate the Xpath as in

Aaand 我设法找到了解决方案,这很简单,只是添加了 [text()="Form3"]/.../" 来预测 Xpath,如

SELECT         
ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/*[local-name()="Form"][text()="Form3"]/text()') as form, 
 ExtractValue(Value(p),'/Customer/Loyalty/Client/Identifications/Identification/Form[text()="Form3"]/.../*[local-name()="value"]/text()') as value

Also extracted the values just sending them directly into the procedure's OUT parameter:

还提取了直接将它们发送到过程的 OUT 参数中的值:

P_FORM := r.form;
P_LOYALTY_VALUE := r.value;

回答by Frank Ockenfuss

with this sql you should get the desired value:

使用此 sql,您应该获得所需的值:

with data as
 (select '<Customer>
   <Loyalty>
   <Client>
      <Identifications>
          <Identification>
               <Form>Form1</Form>
               <value>1234</value>
          </Identification>
          <Identification>
               <Form>Form2</Form>
               <value>4442</value>
          </Identification>
          <Identification>
               <Form>Form3</Form>
               <value>9995</value>
          </Identification>
       </Identifications>
   </Client>
</Loyalty>
</Customer>' as xmlval
    from dual b)
 (SELECT t.val
    FROM data d,
         xmltable('/Customer/Loyalty/Client/Identifications/Identification'
                  PASSING xmltype(d.xmlval) COLUMNS 
                  form VARCHAR2(254) PATH './Form',
                  val VARCHAR2(254) PATH './value') t
   where t.form = 'Form3');

回答by Arkadiusz ?ukasiewicz

When you don't know exact path.

当您不知道确切路径时。

select * from 
xmltable('for $i in $doc//*/Form
 where $i = "Form2"
 return $i/../value'
passing 
xmltype('<Customer>
    <Loyalty>
       <Client>
          <Identifications>
              <Identification>
                   <Form>Form1</Form>
                   <value>1234</value>
              </Identification>
              <Identification>
                   <Form>Form2</Form>
                   <value>4442</value>
              </Identification>
              <Identification>
                   <Form>Form3</Form>
                   <value>9995</value>
              </Identification>
           </Identifications>
       </Client>
    </Loyalty>
 </Customer>') as "doc" ) 

回答by Alessandro Rossi

To extract the value you're looking for you can use the following XPATH expression:

要提取您要查找的值,您可以使用以下 XPATH 表达式:

/Customer/Loyalty/Client/Identifications/Identification/Form[text()='Form3']/../value

Test it here

在这里测试

Then you can use XMLTABLE function to get the result

然后你可以使用 XMLTABLE 函数来获取结果

SELECT my_value
FROM xmltable(
        '/Customer/Loyalty/Client/Identifications/Identification/Form[text()=''Form3'']/../value'
        PASSING xmltype(
'<Customer>
    <Loyalty>
        <Client>
        <Identifications>
            <Identification>
                <Form>Form1</Form>
                <value>1234</value>
            </Identification>
            <Identification>
                <Form>Form2</Form>
                <value>4442</value>
            </Identification>
            <Identification>
                <Form>Form3</Form>
                <value>9995</value>
            </Identification>
        </Identifications>
        </Client>
    </Loyalty>
</Customer>')
        COLUMNS
            my_value VARCHAR2(4000) path '/value'
    )