Python 熊猫重置索引似乎不起作用？
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Pandas reset index doesn't seem to work?
提问by Learning stats by example
I'm not sure where I am astray but I cannot seem to reset the index on a dataframe.
我不确定我在哪里误入歧途，但我似乎无法重置数据帧上的索引。
When I run test.head(), I get the output below:
当我运行时test.head()，我得到以下输出：
As you can see, the dataframe is a slice, so the index is out of bounds.
What I'd like to do is to reset the index for this dataframe. So I run test.reset_index(drop=True). This outputs the following:
如您所见，数据帧是一个切片，因此索引越界。我想做的是重置此数据框的索引。所以我跑test.reset_index(drop=True)。这将输出以下内容：
That looks like a new index, but it's not. Running test.headagain, the index is still the same. Attempting to use lambda.applyor iterrows()creates problems with the dataframe.
这看起来像是一个新索引，但事实并非如此。test.head再次运行，索引还是一样。尝试使用数据框lambda.apply或iterrows()创建数据框问题。
How can I really reset the index?
我怎样才能真正重置索引？
采纳答案by Learning stats by example
BrenBarn's answer works.
布伦巴恩的回答有效。
The following also worked via this thread, which isn't a troubleshooting so much as an articulation of how to reset the index:
以下内容也通过此线程工作，这与其说是故障排除，不如说是说明如何重置索引：
test = test.reset_index(drop=True)
回答by BrenBarn
reset_indexby default does not modify the DataFrame; it returns a newDataFrame with the reset index. If you want to modify the original, use the inplaceargument: df.reset_index(drop=True, inplace=True). Alternatively, assign the result of reset_indexby doing df = df.reset_index(drop=True).
reset_index默认不修改DataFrame；它返回一个带有重置索引的新DataFrame。如果要修改原始文件，请使用inplace参数：df.reset_index(drop=True, inplace=True)。或者，reset_index通过执行分配结果df = df.reset_index(drop=True)。
回答by Subspacian
I would add to in code veritas's answer:
我会在代码 veritas 的回答中添加：
If you already have an index column specified, then you can save the del, of course. In my hypothetical example:
如果您已经指定了索引列，那么您当然可以保存 del。在我的假设示例中：
df_total_sales_customers = pd.DataFrame({'Sales': total_sales_customers['Sales'],
'Customers': total_sales_customers['Customers']}, index = total_sales_customers.index)
df_total_sales_customers = df_total_sales_customers.reset_index()
回答by Wendao Liu
As an extension of in code veritas's answer... instead of doing delat the end:
作为代码 veritas答案的扩展......而不是del在最后做：
test = test.reset_index()
del test['index']
You can set drop to True.
您可以将 drop 设置为True.
test = test.reset_index(drop=True)
