oracle 如何做一个函数来从 pl/sql 中的表中返回行类型？
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时间：2020-09-19 03:12:35 来源:igfitidea点击:
how to do a function to return row type from a table in pl/sql?
提问by Sara
I made this function but it return an error when i execute it!
我做了这个函数，但是当我执行它时它返回一个错误！
create or replace function get_accounts
(Acc_id in Account1.account_id%Type)
return account1%rowtype
as
l_cust_record account1%rowtype;
begin
select * into l_cust_record from account1
where account_id=Acc_id;
return(l_cust_record);
end;
/
采纳答案by MT0
Oracle Setup:
甲骨文设置：
CREATE TABLE account1 (
account_id INT,
name VARCHAR2(20)
);
INSERT INTO account1 VALUES ( 1, 'Bob' );
CREATE OR REPLACE FUNCTION get_accounts(
Acc_id IN Account1.account_id%TYPE
) RETURN account1%ROWTYPE
AS
l_cust_record account1%ROWTYPE;
BEGIN
SELECT *
INTO l_cust_record
FROM account1
WHERE account_id = Acc_id;
RETURN l_cust_record;
END;
/
PL/SQL Block:
PL/SQL 块：
DECLARE
r_acct ACCOUNT1%ROWTYPE;
BEGIN
r_acct := get_accounts( 1 );
DBMS_OUTPUT.PUT_LINE( r_acct.name );
END;
/
Output:
输出：
Bob
回答by GriffeyDog
To call a function in Oracle, you need to use its return value. That is, you can't call it as you would a procedure. Something like this would work:
要在 Oracle 中调用函数，您需要使用其返回值。也就是说，您不能像调用过程那样调用它。像这样的事情会起作用：
declare
myrow account1%rowtype;
account_id Account1.account_id%Type := <VALID ACCOUNT ID VALUE>;
begin
myrow := Get_Accounts(account_id);
end;
/
