PHP：如何在给定日期输入的情况下获得星期日和星期六？
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PHP: How to get Sunday and Saturday given a date input?
提问by marknt15
How can I get the Sunday and Saturday of the week given a specific date?
如何获得给定特定日期的一周中的星期日和星期六？
For example:
例如：
input: Monday, September 28, 2009
output should be:
Sunday, September 27, 2009 12:00 AM - Saturday, October 3, 2009 11:59 PM
输入：2009 年 9 月 28 日，星期一
输出应该是：
2009 年 9 月 27 日星期日上午 12:00 - 2009 年 10 月 3 日星期六晚上 11:59
I am thinking of using the date, strtotime, mktimeand timephp functions.
我想用的date，strtotime，mktime和timePHP函数。
If you have a usable function then it is also fine with me.
如果您有可用的功能，那么我也可以。
Thanks in advance :)
提前致谢 ：）
Cheers, Mark
干杯，马克
回答by cletus
You use strtotime()and date():
你使用strtotime()和date()：
<?php
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
$start = strtotime('last sunday, 12pm', $time);
$end = strtotime('next saturday, 11:59am', $time);
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";
?>
outputs:
输出：
Input: Monday, September 28, 2009
Output: Sunday, September 27, 2009 12:00 PM - Saturday, October 3, 2009 11:59 AM
回答by cletus
<?php
date_default_timezone_set('Europe/London');
$datetime = new DateTime("2009-09-23 12:00:00");
// Saturday
$datetime->setISODate(2009, $datetime->format("W"), 6);
print "Saturday:" . $datetime->format(DATE_ATOM) . "\n";
// Sunday
$datetime->setISODate(2009, $datetime->format("W"), 0);
print "Sunday: " . $datetime->format(DATE_ATOM) . "\n";
?>
回答by RageZ
回答by garrizaldy
echo date("Y-m-d H:i:s", strtotime("last sunday", time()));
echo date("Ymd H:i:s", strtotime("last sunday", time()));
echo date("Y-m-d H:i:s", strtotime("next saturday", time()));
echo date("Ymd H:i:s", strtotime("下周六", time()));
回答by Warren Landis
the issue with the 'correct' answer is, what if the supplied date is Sunday? Then it will give you the previous Sunday, instead of the current Sunday. Same issue with Saturday.
“正确”答案的问题是，如果提供的日期是星期日怎么办？然后它会给你上一个星期天，而不是当前的星期天。周六也有同样的问题。
$s = 'Monday, September 28, 2009';
$time = strtotime($s);
if(date('D', $time) == "Sun"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('last sunday, 12pm', $time);
}
if(date('D', $time) == "Sat"){
$start = strtotime(' 12pm', $time);
}
else {
$start = strtotime('next saturday, 12pm', $time);
}
$format = 'l, F j, Y g:i A';
$start_day = date($format, $start);
$end_day = date($format, $end);
header('Content-Type: text/plain');
echo "Input: $s\nOutput: $start_day - $end_day";
回答by Kavita Mantri
Get Sunday Php Code:
获取周日 PHP 代码：
echo "Today Is : " . date("d-m-Y");
$dw = date( "w");
$dw = 7-$dw;
echo "\nNext Sunday Is" .date('d-m-Y', strtotime("+$dw days"));
回答by Daniel Iser
This is what your looking for. It is what I use.
这就是你要找的。这是我使用的。
$beginningOfWeek = date('Y-m-d H:i:s', strtotime('last Sunday'));
$endOfWeek = date('Y-m-d H:i:s', strtotime('+6 day', strtotime('last Sunday')) );
回答by Norman
You may find my Date Time Helper much handy in this case , it can finish in 3 Lines
在这种情况下，您可能会发现我的 Date Time Helper 非常方便，它可以在 3 行中完成
http://normandqq.github.io/Date-Time-Helper/
http://normandqq.github.io/Date-Time-Helper/
$date = '2013-08-11';
$monday = Model_DTHpr::getMondayByDate($date);
$sunday = Model_DTHpr::adjustDays("add",$monday,6);
Out Put:
输出：
2013-08-05 //Monday
2013-08-11 //Sunday
回答by Palo Verde
strtotime
时间
$input = strtotime("Monday, September 28, 2009");
$nextSunday = strtotime("next Sunday",$input);
回答by meder omuraliev
<?php
$date = strtotime('Monday, September 28, 2009 - 1 day');
$initialString = date('l, F d, Y g:i A', $date);
$end = date('l, F d, Y g:i A', strtotime( 'next saturday 11:59 pm', $date));
echo $initialString . ' - ' . $end;
output: Sunday, September 27, 2009 12:00 AM - Saturday, October 03, 2009 11:59 PM
输出： 2009 年 9 月 27 日星期日上午 12:00 - 2009 年 10 月 3 日星期六晚上 11:59
