Bash 将纪元转换为日期，显示错误的时间
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Bash convert epoch to date, showing wrong time
提问by bobbyrne01
How come date is converting to wrong time?
为什么日期转换为错误的时间？
result=$(ls /path/to/file/File.*)
#/path/to/file/File.1361234760790
currentIndexTime=${result##*.}
echo "$currentIndexTime"
#1361234760790
date -d@"$currentIndexTime"
#Tue 24 Oct 45105 10:53:10 PM GMT
回答by andrewdotn
This particular timestamp is in milliseconds since the epoch, not the standard seconds since the epoch. Divide by 1000:
这个特定的时间戳是自纪元以来的毫秒数，而不是自纪元以来的标准秒数。除以 1000：
$ date -d @1361234760.790
Mon Feb 18 17:46:00 MST 2013
回答by Richard Jessop
You can use bash arithmetic expansion to perform the division:
您可以使用 bash 算术扩展来执行除法：
date -d @$((value/1000))
Note that "value" is a bash variable with the $being optional; i.e., $valueor valuecan be used.
请注意，“ value” 是一个 bash 变量，它$是可选的；即，$value或value可以使用。
回答by Marcus
For Mac OS X, it's date -r <timestamp_in_seconds_with_no_fractions>
对于 Mac OS X，它是 date -r <timestamp_in_seconds_with_no_fractions>
$ date -r 1553024528
Tue Mar 19 12:42:08 PDT 2019
or
或者
$ date -r `expr 1553024527882 / 1000`
Tue Mar 19 12:42:07 PDT 2019
or
或者
$ date -r $((1553024527882/1000))
Tue Mar 19 12:42:07 PDT 2019
