bash 从字符串中删除所有出现的单词

Remove all occurrences of a word from a string

提问by MOHAMED

I have the following string

我有以下字符串

str="toto1 toto2 toto3 toto4 toto2 toto5"

the toto2occurs twice in the string. How can I remove all toto2occurrences from the string?

在toto2字符串中出现了两次。如何toto2从字符串中删除所有出现的内容？

I tried this:

我试过这个：

echo ${str/toto2/}

But this will remove only the first occurrence of toto2.

但这只会删除第一次出现的toto2.

toto1 toto3 toto4 toto2 toto5 # output

How can I remove all toto2occurrences from the string?

如何toto2从字符串中删除所有出现的内容？

回答by MOHAMED

Found it. the solution is:

找到了。解决办法是：

echo ${str//toto2/}