string 用任意数量的空格分割一个字符串
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Split a string by any number of spaces
提问by Stu
I have the following string:
我有以下字符串：
[1] "10012 ---- ---- ---- ---- CAB UNCH CAB"
I want to split this string by the gaps, but the gaps have a variable number of spaces. Is there a way to use strsplit()function to split this string and return a vector of 8 elements that has removed all of the gaps?
我想通过间隙分割这个字符串，但间隙有可变数量的空格。有没有办法使用strsplit()函数来分割这个字符串并返回一个包含 8 个元素的向量，该向量已删除所有间隙？
One line of code is preferred.
一行代码是首选。
回答by A5C1D2H2I1M1N2O1R2T1
Just use strsplitwith \\s+to split on:
只需使用strsplitwith\\s+即可拆分：
x <- "10012 ---- ---- ---- ---- CAB UNCH CAB"
x
# [1] "10012 ---- ---- ---- ---- CAB UNCH CAB"
strsplit(x, "\s+")[[1]]
# [1] "10012" "----" "----" "----" "----" "CAB" "UNCH" "CAB"
length(.Last.value)
# [1] 8
Or, in this case, scanalso works:
或者，在这种情况下，scan也有效：
scan(text = x, what = "")
# Read 8 items
# [1] "10012" "----" "----" "----" "----" "CAB" "UNCH" "CAB"
回答by rnso
strsplit function itself works, by simply using strsplit(ss, " +"):
strsplit 函数本身可以工作，只需使用strsplit(ss, " +")：
ss = "10012 ---- ---- ---- ---- CAB UNCH CAB"
strsplit(ss, " +")
[[1]]
[1] "10012" "----" "----" "----" "----" "CAB" "UNCH" "CAB"
HTH
HTH
