bash OpenVPN 源变量不适用于 debian
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OpenVPN Source vars not working on debian
提问by il0venoobs
I have to create a script to setup an OpenVPN server automatically. In this script I need to source the vars file in /etc/openvpn/easy-rsa/
我必须创建一个脚本来自动设置 OpenVPN 服务器。在这个脚本中，我需要在 /etc/openvpn/easy-rsa/ 中获取 vars 文件
But when I'm executing the following script in the /etc/openvpn/easy-rsa/ folder (with chmod 775 on the script and vars file) it says "xxxx.sh: 3: xxxx.sh: source: not found:"
但是，当我在 /etc/openvpn/easy-rsa/ 文件夹（脚本和 vars 文件上带有 chmod 775）中执行以下脚本时，它说“xxxx.sh: 3: xxxx.sh: source: not found: ”
#!/bin/bash
source ./vars
When I write . ./vars, it works, but then if I want to do a ./clean-all it says :
当我写 . ./vars，它可以工作，但是如果我想做一个 ./clean-all 它说：
Please source the vars script first (i.e. "source ./vars") Make sure you have edited it to reflect your configuration.
请首先获取 vars 脚本（即“source ./vars”） 确保您已编辑它以反映您的配置。
When I do the ./clean-all in the same script than the . ./vars, it works.
当我在与 . ./vars，它有效。
Thanks for your help (and sorry for my bad english :/)
感谢您的帮助（并为我的英语不好：/）
采纳答案by Josh Jolly
When you source(or .) a file, all the commands inside it are read and executed - this includes variable assignments. However, when a variable assignment takes place, it takes place only for the current shell. When you run a script, a subshell is created - so any variables inside the script are only visible within the subshell, not the parent (calling) shell. This is why it works when you have run sourceand clean-allwithin the same script, it should also work if you do both from the command line, ie:
当你source（或.）一个文件时，它里面的所有命令都会被读取和执行——这包括变量赋值。然而，当变量赋值发生时，它只发生在当前 shell 中。当您运行脚本时，会创建一个子外壳 - 因此脚本内的任何变量仅在子外壳中可见，而不是父（调用）外壳。这就是为什么它在您运行source并clean-all在同一个脚本中工作时，如果您从命令行执行这两项操作，它也应该工作，即：
$ . /etc/openvpn/easy-rsa/vars
$ /etc/openvpn/easy-rsa/clean-all
