java检查时间更长
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java check time is greater time
提问by RookieCookie
Hi I'm trying to check if the currentime is > , say, 14:00. Does anyone know how to do this?
嗨，我正在尝试检查当前时间是否 > ，例如 14:00。有谁知道如何做到这一点？
This is what I have:
这就是我所拥有的：
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyyMMdd HH:mm");
Somehow I guess I need to now create a Date object and use this dateformat?
不知何故，我想我现在需要创建一个 Date 对象并使用此日期格式？
I know the current time is:
我知道当前时间是：
date= new Date();
and in the above format it would be return dateFormat.format(date);
在上述格式中，它将返回 dateFormat.format(date);
So can anyone help - much appreciated. (am using Java 7 btw)
任何人都可以提供帮助 - 非常感谢。（顺便说一句，我正在使用 Java 7）
回答by Aaron Digulla
Use Date.compareTo():
Date now = new Date();
Date date = dateFormat.parse(...);
if( now.compareTo( date) < 0 ) {
... date is in the future ...
}
But note that java.util.Date and all related classes have many quirks and subtle bugs. You will make your life much easier by using joda-time:
但请注意 java.util.Date 和所有相关类都有许多怪癖和微妙的错误。使用joda-time会让你的生活更轻松：
DateTime now = DateTime.now();
DateTime date = dateFormat.parse(...); // see http://joda-time.sourceforge.net/userguide.html#Input_and_Output
if( now.isBefore(date) ) {
... date is in the future ...
}
回答by Developer Marius ?il?nas
To check if one date is earlier than another you could use Calendar.
要检查一个日期是否早于另一个日期，您可以使用日历。
Date yourDate = new Date();
Date yourDateToCompareAgainst = new Date();
Calendar calendar = Calendar.getInstance();
calendar.setTime(yourDateToCompareAgainst);
calendar.set(HOUR, 14);
/** You can then check for your condition */
if( calendar.before(yourDate) ) {
}
回答by Kevin Bhuva
You can use Calendar from java.util to achieve this. hope this helps.
您可以使用 java.util 中的 Calendar 来实现这一点。希望这可以帮助。
回答by Ruchira Gayan Ranaweera
Try something like this
尝试这样的事情
SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm");
Date date = new Date();
System.out.println(dateFormat.format(date));
if(date.after(dateFormat.parse("14:00"))){
System.out.println("Current time greater than 14.00");
}
回答by K.D
Try below code, it should work.
试试下面的代码，它应该可以工作。
Date date = new Date() ;
SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm") ;
dateFormat.format(date);
System.out.println(dateFormat.format(date));
if(dateFormat.parse(dateFormat.format(date)).after(dateFormat.parse("12:07")))
{
System.out.println("Current time is greater than 12.07");
}else{
System.out.println("Current time is less than 12.07");
}
回答by Tarik Chakur
Using Gregorian Calendar hope this helps ;)
使用公历希望这会有所帮助；)
public Class Time {
public static void main() {
Calendar C = new GregorianCalendar();
int hour = C.get( Calendar.HOUR_OF_DAY );
int minute = C.get( Calendar.MINUTE );
if( hour == 14 && minute > 0 )
System.out.println("time > 14");
}
}
回答by Ferhat KO?ER
This Function check string times (12:00:10 > 12:00:00 etc...)
此函数检查字符串时间（12:00:10 > 12:00:00 等...）
public static boolean biggerThanTime(String time1,String time2){
String hhmmss1[] = time1.split(":");
String hhmmss2[] = time2.split(":");
for (int i = 0; i < hhmmss1.length; i++) {
if(Integer.parseInt(hhmmss1[i])>Integer.parseInt(hhmmss2[i]))
return true;
}
return false;
}
回答by Chandu Bammidi
TRY THIS ONCE
试试这个
import java.util.*;
import java.time.*;
class one_part
{
public static void main(String []args)
{
LocalTime present=LocalTime.now();
String bf1="07:00:00";
String bf2="10:30:00";
LocalTime bf3 = LocalTime.parse(bf1);
LocalTime bf4 = LocalTime.parse(bf2);
String lunch1="11:30:00";
String lunch2="15:00:00";
LocalTime lunch3=LocalTime.parse(lunch1);
LocalTime lunch4=LocalTime.parse(lunch2);
String dinner1="19:30:00";
String dinner2="22:30:00";
LocalTime dinner3=LocalTime.parse(dinner1);
LocalTime dinner4=LocalTime.parse(dinner2);
if(present.isAfter(bf3) && present.isBefore(bf4))
{
System.out.println("this is breakfast time");
}
else if(present.isAfter(lunch3) && present.isBefore(lunch4))
{
System.out.println("This is lunch time");
}
else if(present.isAfter(dinner3) && present.isBefore(dinner4))
{
System.out.println("This is dinner time");
}
else
{
System.out.println("Restaurent closed");
}
}
}
