MySql 错误:无法更新存储函数/触发器中的表,因为它已被调用此存储函数/触发器的语句使用

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时间:2020-08-31 16:49:03  来源:igfitidea点击:

MySql Error: Can't update table in stored function/trigger because it is already used by statement which invoked this stored function/trigger

mysqltriggers

提问by Mitesh Mynee

I am running a MySQL Query. But when a new row is added from form input I get this error:

我正在运行一个 MySQL 查询。但是当从表单输入添加新行时,我收到此错误:

Error: Can't update table 'brandnames' in stored function/trigger because it is 
already used by statement which invoked this stored function/trigger.

From the code:

从代码:

CREATE TRIGGER `capital` AFTER INSERT ON `brandnames`
FOR EACH
ROW UPDATE brandnames
SET bname = CONCAT( UCASE( LEFT( bname, 1 ) ) , LCASE( SUBSTRING( bname, 2 ) ) )

What does this error mean?

这个错误是什么意思?

回答by Steve

You cannot change a table while the INSERT trigger is firing. The INSERT might do some locking which could result in a deadlock. Also, updating the table from a trigger would then cause the same trigger to fire again in an infinite recursive loop. Both of these reasons are why MySQL prevents you from doing this.

当 INSERT 触发器触发时,您不能更改表。INSERT 可能会进行一些锁定,这可能会导致死锁。此外,从触发器更新表会导致相同的触发器在无限递归循环中再次触发。这两个原因都是 MySQL 阻止您这样做的原因。

However, depending on what you're trying to achieve, you can access the new values by using NEW.fieldname or even the old values--if doing an UPDATE--with OLD.

但是,根据您要实现的目标,您可以使用 NEW.fieldname 或什至旧值(如果执行 UPDATE)访问新值(如果使用 OLD)。

If you had a row named full_brand_nameand you wanted to use the first two letters as a short name in the field small_nameyou could use:

如果您有一行命名full_brand_name并且您想使用前两个字母作为字段中的短名称,small_name您可以使用:

CREATE TRIGGER `capital` BEFORE INSERT ON `brandnames`
FOR EACH ROW BEGIN
  SET NEW.short_name = CONCAT(UCASE(LEFT(NEW.full_name,1)) , LCASE(SUBSTRING(NEW.full_name,2)))
END

回答by rsanchez

The correct syntax is:

正确的语法是:

FOR EACH ROW SET NEW.bname = CONCAT( UCASE( LEFT( NEW.bname, 1 ) )
                                   , LCASE( SUBSTRING( NEW.bname, 2 ) ) )

回答by gerrit_hoekstra

A "BEFORE-INSERT"-trigger is the only way to realize same-table updates on an insert, and is only possible from MySQL 5.5+. However, the value of an auto-increment field is only available to an "AFTER-INSERT" trigger - it defaults to 0 in the BEFORE-case. Therefore the following example code which would set a previously-calculated surrogate key value based on the auto-increment value idwill compile, but not actually work since NEW.id will always be 0:

“BEFORE-INSERT”触发器是在插入时实现同表更新的唯一方法,并且只能从 MySQL 5.5+ 开始。但是,自动增量字段的值仅适用于“AFTER-INSERT”触发器 - 在 BEFORE 情况下默认为 0。因此,以下示例代码将根据自动增量值设置先前计算的代理键值id,但实际上不会工作,因为 NEW.id 将始终为 0:

create table products(id int not null auto_increment, surrogatekey varchar(10), description text);
create trigger trgProductSurrogatekey before insert on product
for each row set NEW.surrogatekey = 
  (select surrogatekey from surrogatekeys where id = NEW.id);

回答by B?o Nam

I have the same problem and fix by add "new." before the field is updated. And I post full trigger here for someone to want to write a trigger

我有同样的问题并通过添加“新”来修复。在字段更新之前。我在这里发布了完整的触发器,供想要编写触发器的人使用

DELIMITER $$

USE `nc`$$

CREATE
    TRIGGER `nhachung_province_count_update` BEFORE UPDATE ON `nhachung` 
    FOR EACH ROW BEGIN

    DECLARE slug_province VARCHAR(128);
    DECLARE slug_district VARCHAR(128);

    IF old.status!=new.status THEN  /* neu doi status */
        IF new.status="Y" THEN
            UPDATE province SET `count`=`count`+1 WHERE id = new.district_id;
        ELSE 
            UPDATE province SET `count`=`count`-1 WHERE id = new.district_id;
        END IF;
    ELSEIF old.province_id!=new.province_id THEN /* neu doi province_id + district_id */

        UPDATE province SET `count`=`count`+1 WHERE id = new.province_id; /* province_id */
        UPDATE province SET `count`=`count`-1 WHERE id = old.province_id;
        UPDATE province SET `count`=`count`+1 WHERE id = new.district_id; /* district_id */
        UPDATE province SET `count`=`count`-1 WHERE id = old.district_id;

        SET slug_province = ( SELECT slug FROM province WHERE id= new.province_id LIMIT 0,1 );
        SET slug_district = ( SELECT slug FROM province WHERE id= new.district_id LIMIT 0,1 );
        SET new.prov_dist_url=CONCAT(slug_province, "/", slug_district);

    ELSEIF old.district_id!=new.district_id THEN 

        UPDATE province SET `count`=`count`+1 WHERE id = new.district_id;
        UPDATE province SET `count`=`count`-1 WHERE id = old.district_id;

        SET slug_province = ( SELECT slug FROM province WHERE id= new.province_id LIMIT 0,1 );
        SET slug_district = ( SELECT slug FROM province WHERE id= new.district_id LIMIT 0,1 );
        SET new.prov_dist_url=CONCAT(slug_province, "/", slug_district);

    END IF;


    END;
$$

DELIMITER ;

Hope this help someone

希望这有助于某人

回答by rf1234

@gerrit_hoekstra wrote: "However, the value of an auto-increment field is only available to an "AFTER-INSERT" trigger - it defaults to 0 in the BEFORE-case."

@gerrit_hoekstra 写道:“但是,自动增量字段的值仅适用于“AFTER-INSERT”触发器——在 BEFORE 情况下它默认为 0。

That is correct but you can select the auto-increment field value that will be inserted by the subsequent INSERT quite easily. This is an example that works:

这是正确的,但您可以很容易地选择将由后续 INSERT 插入的自动增量字段值。这是一个有效的例子:

CREATE DEFINER = CURRENT_USER TRIGGER `lgffin`.`variable_BEFORE_INSERT` BEFORE INSERT 
ON `variable` FOR EACH ROW
BEGIN
    SET NEW.prefixed_id = CONCAT(NEW.fixed_variable, (SELECT `AUTO_INCREMENT`
                                                FROM  INFORMATION_SCHEMA.TABLES
                                                WHERE TABLE_SCHEMA = 'lgffin'
                                                AND   TABLE_NAME   = 'variable'));      
END